Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.
Answer:
64 units2
Step-by-step explanation:
16 x 8 / 2 =
128 / 2 =
64
Hope that helps!
9 .... juhh add the long sides all together !!
So,
First, we will find the surface area of the garden in feet.
(70)(45) = 3150 square ft.
Next, to find the surface area of the garden inches, we need to recall the conversion rate between feet and inches.
1 ft. = 12 in.
So, multiply 3150 by 12.
(3150)(12) = 37,800 square in.
To find the surface area of the garden in yards, we need to recall the conversion rate between yards and feet.
1 yd. = 3 ft.
So, divide 3150 by 3.
Area of the garden in inches: 37,800 square in.
Area of the garden in feet: 3150 square ft.
Area of the garden in yards: 1050 square yd.
Answer:
yessss
Step-by-step explanation:
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