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Nimfa-mama [501]
2 years ago
13

Each side of a pentagon is 10 cm greater than the previous side. If the perimeter of this pentagon is 500 cm, find the lengths o

f the sides.
Mathematics
1 answer:
Vesna [10]2 years ago
8 0

Answer: See explanation

Step-by-step explanation:

The perimeter of a pentagon is gotten through the summation of its five sides. Let the first side be represented by x. Since each side of a pentagon is 10 cm greater than the previous side, then the sides will be:

First side = x

Second side = x + 10

Third side = x + 10 + 10 = x + 20

Forth side = x + 30

Fifty side = x + 40

Therefore,

x + (x + 10) + (x + 20) + (x + 30) + (x + 40) = 500

5x + 100 = 500

5x = 500 - 100

5x = 400

x = 400/5

x = 80

Therefore, the lengths will be:

First side = x = 80cm

Second side = x + 10 = 80 + 10 = 90cm

Third side = x + 20 = 80 + 20 = 100cm

Forth side = x + 30 = 80 + 30 = 110cm

Fifty side = x + 40 = 80 + 40 = 120cm

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Subtract 1316 from both sides:

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On the left side they cancel out and we are left with:

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Ella ran 6 times around her school building. Then she ran 4 miles home.
Snowcat [4.5K]

Answer:

B.6x+4=7

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You can divide the figure as follows:

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3 years ago
Parallelogram PQRS is shown. m/S=(3x), m/R=120, and m/Q=(2y). Find the value of y.A.
fomenos

Option B. From the parallelogram PQRS the value of y is given to be 30

<h3>How to solve for the value of y from the parallelogram</h3>

In order to get the value of y we have to use the formula

2y + 120 = 80

where the value 120 is the angle that is stated as 120 from the question

2y = 180 - 120

2y = 60

y = 60 / 2

y = 30

Hence the value of y = 30

We can go ahead to get the value of x as well

3x + 120 = 180

take the like terms

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