Answer: possible values of Range will be values that are >=91 or <=998
Step-by-step explanation:
Given that :
Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.
Therefore,
given that the smallest value in set Q is a one digit number :
Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)
Also, the largest value in Set Q is a three digit value:
Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).
Therefore, the possible values of the range in SET Q:
The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998
The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91
Answer:
16 cities
Step-by-step explanation:
if 5days = 10 cities
8days=?
applying cross multiplication :
(8days × ten cities )÷5 day
= 16 cities
First lets create an equation for each:
1) Cost = 5x + 60
2) Cost = 11x
Where x is the number of lessons.
Since we want to find the value of x (the number of lessons), we can set both equations equal to each other:
5x + 60 = 11x
Subtract 5x from both sides:
60 = 6x
Divide by 6:
x = 10
So it will take 10 lessons till a member and a nonmember pay the same amount.
The sixteenth one which is
Answer:
(–1, 1)
(4, –2)
Step-by-step explanation:
Let
(x,y) ----> the coordinates of point C
Applying the Pythagoras Theorem
step 1
Find the possibles values of x
Simplify
Solve the quadratic equation
The values of x are
x=-1 and x=4
step 2
Find the possibles values of y
Simplify
Solve the quadratic equation
The values of y are
y=-2, y=1
therefore
The possibles coordinates of point C are
(-1,1),(4,-2)
