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Alex787 [66]
3 years ago
9

John and Jane are married. The probability that John watches a certain television show is .5. The probability that Jane watches

the show is .5. The probability that John watches the show, given that Jane does, is .3. (a) Find the probability that both John and Jane watch the show. (Round your answer to 2 decimal places.) (b) Find the probability that Jane watches the show, given that John does. (Round your answer to 3 decimal places.)
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer: a) 0.15

b) 0.300

Step-by-step explanation:

Given : The probability that John watches a certain television show : P(John)=0.5

The probability that Jane watches the show is : P(Jane)= 0.5.

The probability that John watches the show, given that Jane does

=P(John | Jane)=0 .3.

Using Condition  probability formula P(B|A)=\dfrac{P(A\cap B)}{P(A)}, we have

P(A\cap B)=P(B|A)\timesP(A)

Similarly,

a) The probability that both John and Jane watch the show will be :-

\text{P(John}\cap \text{Jane)}=\text{P(John }|\text{ Jane)}\times\text{P(Jane)}\\\\=0.3\times0.5=0.15

b) The probability that Jane watches the show, given that John does will be :-

\text{P(John }|\text{ Jane)}=\dfrac{\text{P(John}\cap \text{Jane)}}{\text{P(John)}}\\\\=\dfrac{0.15}{0.5}=0.3

Hence, the probability that Jane watches the show, given that John does. = 0.300

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Step-by-step explanation:

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Find sin(a)&cos(B), tan(a)&cot(B), and sec(a)&csc(B).​
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Part B) tan(\alpha)=\frac{4}{\sqrt{33}},\ tan(\beta)=\frac{4}{\sqrt{33}}

Part C) sec(\alpha)=\frac{7}{\sqrt{33}},\ csc(\beta)=\frac{7}{\sqrt{33}}

Step-by-step explanation:

Part A) Find sin(\alpha)\ and\ cos(\beta)

we know that

If two angles are complementary, then the value of sine of one angle is equal to the cosine of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

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Find the value of sin(\alpha) in the right triangle of the figure

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simplify

sin(\alpha)=\frac{4}{7}

therefore

sin(\alpha)=\frac{4}{7}

cos(\beta)=\frac{4}{7}

Part B) Find tan(\alpha)\ and\ cot(\beta)

we know that

If two angles are complementary, then the value of tangent of one angle is equal to the cotangent of the other angle

In this problem

\alpha+\beta=90^o ---> by complementary angles

so

tan(\alpha)=cot(\beta)

<em>Find the value of the length side adjacent to the angle alpha</em>

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Let

x ----> length side adjacent to angle alpha

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simplify

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therefore

sec(\alpha)=\frac{7}{\sqrt{33}}

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