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Alex787 [66]
3 years ago
9

John and Jane are married. The probability that John watches a certain television show is .5. The probability that Jane watches

the show is .5. The probability that John watches the show, given that Jane does, is .3. (a) Find the probability that both John and Jane watch the show. (Round your answer to 2 decimal places.) (b) Find the probability that Jane watches the show, given that John does. (Round your answer to 3 decimal places.)
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Answer: a) 0.15

b) 0.300

Step-by-step explanation:

Given : The probability that John watches a certain television show : P(John)=0.5

The probability that Jane watches the show is : P(Jane)= 0.5.

The probability that John watches the show, given that Jane does

=P(John | Jane)=0 .3.

Using Condition  probability formula P(B|A)=\dfrac{P(A\cap B)}{P(A)}, we have

P(A\cap B)=P(B|A)\timesP(A)

Similarly,

a) The probability that both John and Jane watch the show will be :-

\text{P(John}\cap \text{Jane)}=\text{P(John }|\text{ Jane)}\times\text{P(Jane)}\\\\=0.3\times0.5=0.15

b) The probability that Jane watches the show, given that John does will be :-

\text{P(John }|\text{ Jane)}=\dfrac{\text{P(John}\cap \text{Jane)}}{\text{P(John)}}\\\\=\dfrac{0.15}{0.5}=0.3

Hence, the probability that Jane watches the show, given that John does. = 0.300

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vekshin1

Answer:

DC = 10.93 cm ,  AC = 9.8 cm

Step-by-step explanation:

From trigonometry;

⇒ Tan 60 = AB/BD

⇒AB = BD Tan 60 ( where BD = 4 cm )

⇒ AB = 6.93 cm

Also, AB=BC , therefore;

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From Pythagoras theorem;

⇒ AC^{2} = AB^{2} + BC^{2} = (6.93)^{2} + (6.93)^{2}

⇒ AC = \sqrt{96.05} = 9.80 cm

⇒ DC = BD + BC = 4 + 6.93

⇒ DC = 10.93 cm

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