Answer:
53/5
Step-by-step explanation:
since 10 is the denominator of the denominator we can move it to the numerator, giving us 10n/5-3n = 1/5
multiply all sides by 5-3n, giving us 10n = (5-3n)/5
now multiply by 5 to get rid of the final denomintor, 50n = 5-3n
move 3n to the other side 53n = 5, n = 53/5
Answer:
Not sure if I correctly did it but Stan is 56$ and Kyle is 44$, unless they meant how much they spent and were left with.
Step-by-step explanation:
50 + 6 = 56
34 + 10 = 44
Answer:
Area = 2025 miles²
Perimeter = 180 miles
Step-by-step explanation:
Given the following :
Scale of drawing = 1 inch : 5 miles
Length of side of the scale drawing = 9 inches
To find The actual perimeter and area of the square, we need ;
Actual length of the drawing :
1 inch = 5 miles
9 inches = (5 × 9) miles = 45 miles
Hence,
Area of a square = a²
Where a = side length
Actual side length = 45 miles
Actual area of square = 45² = 2025 miles²
Actual Perimeter of square :
Perimeter of a square = 4a
a = side length
Actual perimeter = 4(45) = 180 miles
Let's first find the number of apple pies.
apple pies = 65 crates x 43 apple pies per crate = 2795 apples pies
If each apple pie cost $12 then...
money from apple pies = 2795 apple pies x $12 = $33540
total pies sold = 2795 apple pie + 121 boxes x 76 sweet potato pies = 11991 pies
Applying Newton's Second Law, it is found that the force, in Newtons, is given by:
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
Newton's Second Law states that Force, in Newtons, is <u>mass times acceleration</u>, that is:

In this problem, mass of 50 kg, thus 
Acceleration is <u>change in velocity divided by change in time</u>, that is:

In this problem, we don't know the velocities, but know that time is from 16s to 21s, thus:


Thus, the force is given by:


![F = 50\frac{[v(21) - v(16)]}{5}](https://tex.z-dn.net/?f=F%20%3D%2050%5Cfrac%7B%5Bv%2821%29%20-%20v%2816%29%5D%7D%7B5%7D)
![F = 10[v(21) - v(16)]](https://tex.z-dn.net/?f=F%20%3D%2010%5Bv%2821%29%20-%20v%2816%29%5D)
A similar problem is given at brainly.com/question/18801986