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2 years ago

Nisha did the work below to solve an equation.

Mathematics

2 answers:

WITCHER [35]2 years ago

7 0

Answer:

C. Step 3

Step-by-step explanation:

allsm [11]2 years ago

4 0

Answer:

It is C, I got it right hopefully it helps.

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Algebra find each unknown 6/12=x/2

bearhunter [10]

Answer:

x=1

Step-by-step explanation:

6/12 = x/2

Simplify the left side by dividing the top and bottom by 6

1/2 = x/2

Using cross products

2x =2

Divide by 2

2x/2 =2/2

x=1

5 0

2 years ago

Just b I need to know, I need explanation also.

Nastasia [14]

Answer:

$\implies \: 2.6851 \text{ \: ft}$

$\\$

Step-by-step explanation:

$\boxed{\boxed{ \blue\bigstar \red{ \bold{ \: \: math \: \: }} \blue\bigstar}}$

$\pink{\implies = \sqrt{ {36.1}^{2} - {36}^{2}} }$

$\orange{ \implies = \sqrt{1303.21} - 1.296}$

$\green{ \implies = \sqrt{7.21} }$

$\red{ \implies = 2.6851 \: \text{ft}}$

4 0

3 years ago

A bag contains pennies, nickles, dimes, and quarters.There are 50 coins in all. Of the coins, 10% are pennies and 32% are dimes.

ikadub [295]

10 pennies, 16 dimes, 19 nickles.
Sorry I'm not from US so I don't know your currency. Sorry about that. Hope what I have given you is enough. :)

8 0

2 years ago

2×y to the power2<br> -6×y to the power 2

sertanlavr [38]

2y to the second power= 4y
-6y to the second power= -36y

4 0

3 years ago

For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of $-0.25$ .

Upon substituting our given values in z-score formula, we will get:

$-0.25=\frac{x-500}{100}$

$-0.25*100=\frac{x-500}{100}*100$

$-25=x-500$

$-25+500=x-500+500$

$x=475$

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0

2 years ago