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Digiron [165]
3 years ago
8

Sally wants to know why the leaves of her plants are turning yellow. She suspects it is because the plants are not receiving eno

ugh nutrients. To test her hypothesis, she devises the following experiment.
First, Sally obtains four identical green plants. Then, she places each plant in separate, but identical pots, with the same type and amount of soil. Although Sally gives each plant the same amount of water and Sun exposure each day, she changes the amount of fertilizer placed in each pot. Finally, she records the number of yellow leaves that she sees in each pot every day over the course of one month.

What is the dependent variable in Sally's experiment?
A.
the number of yellow leaves
B.
the type of green plant
C.
the amount of water
D.
the amount of fertilizer
Biology
2 answers:
OleMash [197]3 years ago
7 0

The correct answer is option A, that is, the number of yellow leaves.  

An independent variable refers to the variable, which is monitored or modified in a scientific experiment to examine the influences on the dependent variable. A dependent variable refers to the variable being measured and examined in a scientific test. Hence, in the given case, the number of leaves getting yellow is a dependent variable.  

Both the dependent and the independent variables may be observed in terms of the cause and effect.  


Jlenok [28]3 years ago
6 0
<h2>Answer:</h2>

The correct answer is option A which is the number of yellow leaves.

<h3>Explanation:</h3>
  • In mathematics modeling , or statistical analysis or in scientific experiments a n independent variable is considered as the input of experiment and it can be changed depending upon the protocols.
  • Dependent variable is the out put of the experiment, that depends upon the independent variable.
  • In the above experiment, sally wants to know about the number of yellow leaves upon changing the fertilizer amount. So input means yellow leaves are dependent variable.
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Answer:

a is the middle gene.

Distance [b-a]= 24.7 mu

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A homozygous wild-type female drosophila (a⁺b⁺c⁺/a⁺b⁺c⁺) is crossed with a homozygous recessive male (abc/abc). <u>The order of the genes here is arbitrary. </u>

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<h3><u>2nd Determine the single crossover gametes</u></h3>

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<h3><u /></h3><h3><u>4) Calculate the distance in map units </u></h3>

Distance (mu) = RF x 100

Distance [b-a]= 0.247 × 100 = 24.7 mu

Distance [a-c]= 0.158 × 100 = 15.8 mu

Distance [b-a} = 24.7 mu + 15.8 mu = 40.5 mu

<h3><u>The gene map therefore looks like: </u></h3>

b------------24.7 mu--------------------------a---------15.8 mu-----------c

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