The average of five unequal positive integers is 11. What is the largest possible value that any of those numbers can have?
1 answer:
Answer:
45
Step-by-step explanation:
The smallest ones can be 1, 2, 3, 4, so the largest will be ...
(1 + 2 + 3 + 4 + n)/5 = 11 . . . . the average of the 5 integers
10 + n = 55
n = 45
The largest one can be 45.
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