Question

The average of five unequal positive integers is 11. What is the largest possible value that any of those numbers can have?

Answer 1

Answer:

45

Step-by-step explanation:

The smallest ones can be 1, 2, 3, 4, so the largest will be ...

(1 + 2 + 3 + 4 + n)/5 = 11 . . . . the average of the 5 integers

10 + n = 55

n = 45

The largest one can be 45.