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polet [3.4K]
4 years ago
5

The diameter of a circle with endpoints A(-1,5) and B(4,-3) Use the midpoint formula to find the coordinates of the center of ci

rcle P(xy)
Mathematics
1 answer:
Nana76 [90]4 years ago
5 0

Answer:

Since all 4 radii are shown to have the same length value of √10, we are confident that our calculations for center C and diameter endpoint E are correct.

Finally, we can also calculate the length of the diameter since it is simply twice the length of the radius:

   radius = √10

   diameter = 2√10

Step-by-step explanation:


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an aircraft carrier leads port heading due west at 28 knots. A helicopter is 175 nautical miles from the carrier at an angle of
emmainna [20.7K]
Let’s say it takes time t hours for the interception.
In that time the carrier travels 28t nm west and the helicopter 130t nm.
Now we use the sine rule to find the angle x which lies between the distance 175 and 130t.
sin(x)/28t=sin35/130t. So sin(x)=28sin35/130=14sin35/65=0.1235 and x=7.0964 degrees.
Therefore the helicopter should use a bearing of 35+7.0964=42.0964 degrees north of east or 47.9 degrees east of north approx.
8 0
3 years ago
Solve 4 over x minus 4 equals the quantity of x over x minus 4, minus four thirds for x and determine if the solution is extrane
Vinil7 [7]
I'm thinking this is what the problem looks like: \frac{4}{x-4}= \frac{x}{x-4}- \frac{4}{3}.  The first thing to do is to move the \frac{x}{x-4} over to the other side because it has a common denominator with the other side.  Doing that and at the same time combining them over their common denominator looks like this: \frac{4-x}{x-4}= -\frac{4}{3}.  The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4).  Distributing through the parenthesis is 12 - 3x = -4x + 16.  Solving for x gives us x = 4.  Of course when we sub a 4 back in for x we get real problems, don't we?  Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.
6 0
3 years ago
Can someone explain to me why are we adding 2kpi when we are doing zeros for sin and cos, but adding kpi when doing zeros for tg
makvit [3.9K]

on the first exercise, you got a solution angle of π/18, that's a good solution for the I Quadrant only, however, on a circle, we have angles that go from 0 to 2π, however we can always keep on going around and continute to 2π + π/2 or 3π or 4π, or 115π/3 or 1,000,000π/18 and so on, and we're really just going around the circle many times over, getting a larger and larger angle, same circular motion.

π/18 on that exercise works for the I Quadrant, however if we continue and go around say 2π, we'll find that 2π/3 + π/18 is a coterminal angle with π/18, and thus that angle has also the same sine value.

π/18 + 2kπ/3 , where k = integer, is a way to say, all angles around the circle that look like this have the same sine, namely

π/18 + 2(1)π/3

π/18 + 2(2)π/3

π/18 + 2(3)π/3

π/18 + 2(5)π/3

π/18 + 2(99999999)π/3

.....

so using the "k" as some sequence multiplier, is a generic notational way to say, "all these angles".

you'll also find that "n" is used as well for the same notation, say for example

2π/3  + 2πn.

8 0
3 years ago
Lily ran 1,000 meters in 12 minutes. How many meters/minute did she run?
vladimir2022 [97]

Answer:

1,000 divided by 12=

aprox 83.3 meters per minute

5 0
3 years ago
There are 946 milliters in a quart there are 2 pints in a quart
devlian [24]

Answer:

Answer: There are 473 milliliters in 1 pint. ... 946 ml in 1 quart

Step-by-step explanation:

3 0
3 years ago
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