Answer:
Percent Composition
1. Find the molar mass of all the elements in the compound in grams per mole.
2. Find the molecular mass of the entire compound.
3. Divide the component's molar mass by the entire molecular mass.
4. You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
You have not mention here about those elements but the general concept for this is the:
uneven distribution ------> polar
even distribution -------> non-polar
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
From the question we are told
Ions, isotope, average atomic mass fill in the blank
Generally
Where
- Z signifies the Proton Number of the atom
- A signifies Mass Number of the atom
Therefore
For Row 1 according to the respective Column is
- Zn^{2+} , 32 ,65 ,32 ,30 ,34 ,2+
For Row 2 according to the respective Column is
- Mn, 25, 55, 25, 25,30, 3-
For Row 3 according to the respective Column is
For Row 4 according to the respective Column is
- O^{2-} , 8 ,16 ,8 ,6 ,8 , 2-
For Row 5 according to the respective Column is
- Na, 11, 23, 11, 10, 12, 1-
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Answer:
Cupric ions
Explanation:
In the single displacement reaction shown, the cupric ions lost two electrons.
Cu²⁺ + 2e⁻ → Cu
The replacement of a metallic ion in solution by a metal atom higher in the activity series than than the metal in solution falls into this category of reactions.
Since Zn higher in the series, it displacements the cupric ions.
