All categories

3 years ago

Write a nuclear equation for the decay of Polonium 211

Chemistry

1 answer:

kumpel [21]3 years ago

3 0

Answer:

₈₄Po²¹¹ → ₈₂Pb²⁰⁷ + ₂He⁴ + energy

Explanation:

Polonium-211 is unstable nuclei. It undergoes alpha decay and produce Pb-207 and alpha particle.

Nuclear equation:

₈₄Po²¹¹ → ₈₂Pb²⁰⁷ + ₂He⁴ + energy

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number less than 4 and atomic number less than 2 as compared to parent atom the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

You might be interested in

Photosynthesis is the process by which most living things convert the chemical energy in glucose into more accessible chemical e

kotykmax [81]

The correct answer is A

3 0

3 years ago

In testing the effectiveness of an antacid compound, 20.0g of Hydrochloric Acid is mixed with 28.0g of Magnesium Hydroxide. Will

BartSMP [9]

Answer:

Base Mg(OH)2 does neutralise the acid and is 12g in excess.

Explanation:

2HCL +Mg(OH)2 -> MgCl2 + 2H20

2 * 36.458 g of HCL react with 58.319 g of Mg(OH)2 to neutralise it.

72.916 HCl reacts with 58.319 g of the base.

So 20 g HCl reacts with (58.319/72.916) * 20 = 16g.

There are 28 g of Mg(OH)2 so the base does neutralise all the acid.

The Mg(OH)2 is 28 - 16 = 12 g in excess.

4 0

3 years ago

The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28

ivanzaharov [21]

Answer: The mass of second isotope of indium is 114.904 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

.....(1)

Let the mass of isotope 2 of indium be 'x'

For isotope 1:

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

For isotope 2:

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

$114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu$

Hence, the mass of second isotope of indium is 114.904 amu

4 0

3 years ago

Can you please help. I don't know how to do it.

Rainbow [258]

The area used to be covered by an ocean

3 0

3 years ago

List three differences between the earth 240 million years ago and the present earth.

raketka [301]

Dinosaurs, cavemen, sabertooth tiger

4 0

3 years ago