Write a nuclear equation for the decay of Polonium 211
1 answer:
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Answer:
Reaction 1 is balanced but 2 is not balanced , the balance equation are :
1.
2.
Explanation:
Balanced Equations : These are the equation which follows the law of conservation of mass .
The total number of atoms present in reactant is equal to total number of atoms present in product.
1.
This is acid - base type reaction where
act as Acid
act as weak base
Reactant : ,
Number of atoms of :
C = 2 () + 1 (
)
= 2 + 1
= 3
H = 4() + 1 (
)
= 4 + 1
5
O = 2() + 3 (
)
= 5
Na = 1 ()
= 1
Product : ,
,
Number of atoms :
C = 1() + 2(
)
= 1 + 2
= 3
H = 2() + 3(
)
= 2 + 3
= 5
O = 1() + 2(
)
+2(
= 1 + 2 + 2
= 5
Na = 1(
= 1
Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction
2.
This is double displacement reaction .
Check the balancing in both reactant and products should be :
Na = 2
H = 2
Ca = 1
C = 2
O = 6
Cl = 2
Answer : The change in entropy is
Explanation :
Formula used :
where,
= change in entropy = ?
m = mass of water = 1.00 kg
= heat of vaporization of water =
T = temperature =
Now put all the given values in the above formula, we get:
Therefore, the change in entropy is