Answer:
T2 =21.52°C
Explanation:
Given data:
Specific heat capacity of sample = 1.1 J/g.°C
Mass of sample = 385 g
Initial temperature = 19.5°C
Heat absorbed = 885 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = Final temperature - initial temperature
885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )
885 J = 423.5 J/°C× (T2 - 19.5°C )
885 J / 423.5 J/°C = (T2 - 19.5°C )
2.02°C = (T2 - 19.5°C )
T2 = 2.02°C + 19.5°C
T2 =21.52°C
Answer is 2KClO3 3O2 + 2KCl
Answer:
A
Explanation:
This is because in the graph shown line A has a quite greater impact of refraction than line B .
Hence, we can conclude that line A has the greater reaction at a faster rate.
If you need half the volume, you need double the pressure (V * p). Normal air pressure in the atmosphere is 101300 Pa so that means you need double that, thus 202600 Pa (or 2,026 bars)
Answer:
You use Bleach, Dimethyl Ammonium Chloride, Sodium Nitrite, Ethyl benzyl Ammonium Chloride, Lemon citrus, Baking soda, ETC
Explanation:
You use these in some of your cleaning supplies and home-made remedies.
