What is the solubility of Na2HAsO4 at 60 degrees C

An atomic radius is about 1.00*10^2 pm. Convert the radius to inches. (1 pm=10^-12m)

natka813 [3]

Answer:

3.937 x 10⁻⁸ inches

Explanation:

Data Given:

Atomic radium in pm (picometer) = 1.00 x 10² pm

Atomic radium in inches = ?

1 pm = 10⁻¹² m

Solution:

First convert picometer to meter

As we Know

1 pm = 10⁻¹² m

then

1.00 x 10² pm = X meter

Do cross multiplication

X meter = (1.00 x 10² pm)(10⁻¹² m) / 1 pm

X meter = 1 x 10⁻⁹ m

So, 1.00 x 10² pm equal to 1 x 10⁻⁹ m

Now convert meter to inches

As

1 m = 39.37 inches

1 x 10⁻⁹ m = X inches

Do cross multiplication

X inches = (39.3701 inches)(1 x 10⁻⁹ m ) / 1 m

X inches = 3.937 x 10⁻⁸ inches

So,

1.00 x 10² pm = 3.937 x 10⁻⁸ inches

so the radius is 3.937 x 10⁻⁸ inches

4 0

2 years ago

How many atoms are in 3N4010

777dan777 [17]

Answer:

of N ( nitrogen): 12

of O (oxygen): 30

5 0

3 years ago

Make the following conversions. Show your calculations.

Natalija [7]

Answer:

1. 500 cm = 5 m

2. 1000 g = 1 kg

3. 455 L = 45, 500 cL

4. 0.865 m = 0.00865 m or 8.65 * 10^-3 n

5. 33.5 cm = 335 mm

6. 0.0198 m = 19800 micrometers

7. 57.65 cg = 5.765 * 10^8 nanograms

8. 1000 L = 1 kl

9. 99 degrees F = 37.222 degrees C

Explanation:

1. One meter = 100 centimeters

500 centimeters/ 100 centimeters = 5 meters

2. One kilogram = 1000 grams.

1000 grams/1000 grams = 1 kilogram

3. One Liter = 100 centiliters

455 liters * 100 centiliters = 45, 500 centiliters

4. One meter = 100 centimeters

0.865 centimeters/100 centimeters = 0.00865 meters

5. One centimeter = 10 millimeters

33.5 centimeters * 10 millimeters = 335 millimeters

6. One meter = 1.0 * 10^6 micrometers

0.0198 meters * 1 * 10^6 micrometers = 19800 micrometers.

7. One centigram = 1.0 * 10^7 nanograms

57.65 centigrams * 1 * 10^7 nanograms = 5.765 * 10^8 nanograms.

8. One kiloliter = 1000 L

1000 L/ 1000 L = 1 kiloliter

9. The formula for finding Celsius is 5/9(f - 32)

So 5/9(99 - 32) = x

5/9(67) = x

x = 335/9 or 37.222 degrees Celsius.

5 0

3 years ago

What is the mass in grams of 1.00 x 10 24 atoms of Mn?

Alex17521 [72]

<h3>Answer:</h3>

91.2 g Mn

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 1.00 × 10²⁴ atoms Mn

<u>Step 2: Identify Conversions</u>

Avogadro's Numer

[PT] Molar Mass of Mn - 54.94 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 1.00 \cdot 10^{24} \ atoms \ Mn(\frac{1 \ mol \ Mn}{6.022 \cdot 10^{23} \ atoms \ Mn})(\frac{54.94 \ g \ Mn}{1 \ mol \ Mn})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 91.2321 \ g \ Mn$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

91.2321 g Mn ≈ 91.2 g Mn

7 0

3 years ago

Read 2 more answers

Please help!!! due soon!

Veseljchak [2.6K]

Answer:

Always stays the same.

7 0

2 years ago