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Dafna1 [17]
4 years ago
10

The mass of a solid substance is 21.112 g. If the volume of the solid substance is 19.5 cm3, calculate the density of the substa

nce (in g/cm3) with the correct number of significant digits. The density is g/cm3.
Chemistry
1 answer:
Ostrovityanka [42]4 years ago
6 0

Answer:

ρ = 1.08 g/cm³

Explanation:

Step 1: Given data

Mass of the substance (m): 21.112 g

Volume of the substance (V): 19.5 cm³

Step 2: Calculate the density of the substance

The density (ρ) of a substance is equal to its mass divided by its volume.

ρ = m / V

ρ = 21.112 g / 19.5 cm³

ρ = 1.08 g/cm³

The density of the substance is 1.08 g/cm³.

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A hot air balloon, when fully inflated, contains 2,800,000 Liter of air. If each mole of air occupies 22.4 L of at a temperature
emmainna [20.7K]

Answer:

1.44 atm

Explanation:

Step 1:

We'll begin by calculating the number of mole in 2,800,000 Liter of air.

I mole of air occupy 22.4L.

Therefore, Xmol of air will occupy 2800000L i.e

Xmol of air = 2800000/22.4

Xmol of air = 125000 moles

Step 2:

Determination of the pressure when the balloon is fully inflated .

This can be obtained as follow:

Number of mole (n) of air = 125000 moles

Volume (V) = 2800000 L

Temperature (T) = 120°C = 120°C + 273 = 393K

Gas constant (R) = 0.082atm.L/Kmol

Pressure (P) =.?

PV = nRT

Divide both side V

P= nRT/V

P= (125000x0.082x393) / 2800000

P = 1.44 atm

Therefore, the pressure of the air when the balloon is fully inflated is 1.44 atm

3 0
3 years ago
In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

  • Ca: 40 g/mole
  • F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

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