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Nonamiya [84]
3 years ago
8

How many moles of O are there in 41.8 grams of O?

Chemistry
1 answer:
il63 [147K]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 2.61 \ mol \ O}}

Explanation:

To convert from grams to moles, the molar mass is used. This number tells us the grams per mole of a substance. It can be found on the Periodic Table. Look for oxygen.

  • Oxygen (O): 15.999 g/mol

Use this number as a ratio.

\frac {15.999 \ g \ O }{ 1 \ mol \ O }

Multiply by the given number of moles.

41.8 \ g \ O *\frac {15.999 \ g \ O }{ 1 \ mol \ O }

Flip the fraction so the grams of oxygen cancel.

41.8 \ g \ O *\frac { 1 \ mol \ O }{ 15.999 \ g \ O}

41.8  *\frac { 1 \ mol \ O }{ 15.999 }

\frac { 41.8 \ mol \ O }{ 15.999 }= 2.61266329146 \ mol \ O

The original measurement of grams has 3 significant figures (4, 1, and 8). Our answer must have the same. For the number we calculated, that is the hundredth place. The 2 in the thousandth place tells us to leave the 1.

2.61 \ mol \ O

41.8 grams of O has 2.61 moles of oxygen.

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Complete question:

Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent  C___________________71

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