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3 years ago

How many moles of O are there in 41.8 grams of O?

Chemistry

1 answer:

il63 [147K]3 years ago

8 0

Answer:

$\boxed {\boxed {\sf 2.61 \ mol \ O}}$

Explanation:

To convert from grams to moles, the molar mass is used. This number tells us the grams per mole of a substance. It can be found on the Periodic Table. Look for oxygen.

Oxygen (O): 15.999 g/mol

Use this number as a ratio.

$\frac {15.999 \ g \ O }{ 1 \ mol \ O }$

Multiply by the given number of moles.

$41.8 \ g \ O *\frac {15.999 \ g \ O }{ 1 \ mol \ O }$

Flip the fraction so the grams of oxygen cancel.

$41.8 \ g \ O *\frac { 1 \ mol \ O }{ 15.999 \ g \ O}$

$41.8 *\frac { 1 \ mol \ O }{ 15.999 }$

$\frac { 41.8 \ mol \ O }{ 15.999 }= 2.61266329146 \ mol \ O$

The original measurement of grams has 3 significant figures (4, 1, and 8). Our answer must have the same. For the number we calculated, that is the hundredth place. The 2 in the thousandth place tells us to leave the 1.

$2.61 \ mol \ O$

41.8 grams of O has 2.61 moles of oxygen.

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3 years ago

Which atoms in the amino acids become the h2o molecule produced by their action in model?

Mariana [72]

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1 year ago

If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered un

Murrr4er [49]

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol$

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

$Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol$

Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

$Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol$

Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

$Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol$

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

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3 years ago

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pantera1 [17]

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