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Nonamiya [84]
3 years ago
8

How many moles of O are there in 41.8 grams of O?

Chemistry
1 answer:
il63 [147K]3 years ago
8 0

Answer:

\boxed {\boxed {\sf 2.61 \ mol \ O}}

Explanation:

To convert from grams to moles, the molar mass is used. This number tells us the grams per mole of a substance. It can be found on the Periodic Table. Look for oxygen.

  • Oxygen (O): 15.999 g/mol

Use this number as a ratio.

\frac {15.999 \ g \ O }{ 1 \ mol \ O }

Multiply by the given number of moles.

41.8 \ g \ O *\frac {15.999 \ g \ O }{ 1 \ mol \ O }

Flip the fraction so the grams of oxygen cancel.

41.8 \ g \ O *\frac { 1 \ mol \ O }{ 15.999 \ g \ O}

41.8  *\frac { 1 \ mol \ O }{ 15.999 }

\frac { 41.8 \ mol \ O }{ 15.999 }= 2.61266329146 \ mol \ O

The original measurement of grams has 3 significant figures (4, 1, and 8). Our answer must have the same. For the number we calculated, that is the hundredth place. The 2 in the thousandth place tells us to leave the 1.

2.61 \ mol \ O

41.8 grams of O has 2.61 moles of oxygen.

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Full question:

This question is incomplete, here it is completed:

An endergonic reaction with a ______ ∆H and a ______ ∆S can be changed into an exergonic reaction by decreasing the temperature.

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Option D: positive, negative

Answer:

Option B: negative, negative

Explanation:

The change in free energy (ΔG) of a system for a constant-temperature process is

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free energy is the energy available to do work. Thus, if a particular reaction is accompanied by a release of usable energy (that is, <u>ΔG is negative</u><u>), it is said to be</u><u> exergonic</u>. On the other hand, if a reaction consumes energy (that is, <u>ΔG is positive</u><u>), it is said to be </u><u>endergonic</u>.

Looking at the equation, we can see that if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS  is smaller in magnitude than ΔH. This condition is met when T is small.

ΔG = ΔH - TΔS

           -        -

This means that the reaction proceeds spontaneously at low temperatures. At high temperatures, the reverse reaction becomes spontaneous. An example of that would be the following reaction:

NH₃(g) + HCl(g) → NH₄Cl(s)

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