Answer:
b) Delta S < 0
Explanation:
The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).
- If Δn(g) > 0, the entropy increases (ΔS > 0).
- If Δn(g) < 0, the entropy decreases (ΔS < 0).
- If Δn(g) = 0, there is little or no change in the entropy
Let's consider the following equation.
2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)
Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.
Answer:
ΔG < 0
Explanation:
The condition for spontaneity of a chemical reaction is that ∆G<0. Hence for any biochemical reaction to proceed as written, ∆G must have a negative value.
If ∆G >0, the reaction is not spontaneous and will not proceed as written. ∆G=0 means that the reaction has attained equilibrium.
B, more kinetic energy means more collisions and thus more reactions according to collision theory.
<u>Answer:</u> The binding energy for lithium-6 nuclei is 3.09 E+11
<u>Explanation:</u>
Binding energy is defined as the energy which holds the nucleus together. It is basically the product of mass defect and the square of the speed of light.
This energy is calculated by using Einstein's equation, which is:

where,
E = Binding energy of the atom
= Mass defect = 0.0343g/mol =
(Conversion factor:
)
c = speed of light = 
Putting values in above equation, we get:

(Conversion factor:
)
Hence, the binding energy for lithium-6 nuclei is 3.09 E+11
Answer:

Explanation:
From the question we are told that:
Initial volume 
Final Volume
Work 
Temperature 
Generally the equation for Ideal gas is mathematically given by



