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lbvjy [14]
3 years ago
8

Using a spectrophotometer, and a cuvette with a path length of 1 cm you measure the absorbance (A275) of Guanosine to be 0.70. C

alculate the concentration of guanosine in your sample
Chemistry
1 answer:
Anton [14]3 years ago
5 0

Answer : The concentration of guanosine in your sample is, 8.33\times 10^{-5}M

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

where,

A = absorbance of solution  = 0.70

C = concentration of solution = ?

l = path length = 1.00 cm

\epsilon = molar absorptivity coefficient guanosine  = 8400M^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

0.70=8400M^{-1}cm^{-1}\times C\times 1.00cm

C=8.33\times 10^{-5}M

Thus, the concentration of guanosine in your sample is, 8.33\times 10^{-5}M

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Barrier islands typically have sand in the beach zone and dune field, and mud in the back-barrier. Overwash deposits sand in the back-barrier.

Barrier islands form in three ways. They can form from spits, from drowned dune ridges or from sand bars. Longshore drift is the movement of sand parallel to the shore caused by the angle of the waves breaking on the beach. ... When a storm such as a hurricane digs an inlet through the spit a barrier island is formed.

7 0
3 years ago
How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?
loris [4]
<h3>Answer:</h3>

427 g Mo

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

<u>Step 3: Convert</u>

<u />2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \  Mo} ) = 426.966 g Mo

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

426.966 g Mo ≈ 427 g Mo

3 0
3 years ago
What is the pH of a buffer solution upon mixing 15.0 mL of 0.40 M HCl and 20.0 mL of 0.50 M NH? Kb (NH3) = 1.8 x 10 E. 7.00 A. 9
vladimir2022 [97]

<u>Answer:</u> The pH of resulting solution is 9.08

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}       ........(1)

  • <u>For HCl:</u>

Molarity of HCl = 0.40 M

Volume of solution = 15.0 mL

Putting values in equation 1, we get:

0.40M=\frac{\text{Moles of HCl}\times 1000}{15.0mL}\\\\\text{Moles of HCl}=0.006mol

  • <u>For ammonia:</u>

Molarity of ammonia = 0.50 M

Volume of solution = 20.0 mL

Putting values in equation 1, we get:

0.50M=\frac{\text{Moles of ammonia}\times 1000}{20.0mL}\\\\\text{Moles of ammonia}=0.01mol

The chemical reaction for hydrochloric acid and ammonia follows the equation:

                  HCl+NH_3\rightarrow NH_4Cl

Initial:          0.006      0.01

Final:             -         0.004              0.006

Volume of solution = 15.0 + 20.0 = 35.0 mL = 0.035 L    (Conversion factor:  1 L = 1000 mL)

  • To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

pOH=pK_b+\log(\frac{[salt]}{[base]})

pOH=pK_b+\log(\frac{[NH_4Cl]}{[NH_3]})

We are given:

pK_b = negative logarithm of base dissociation constant of ammonia = -\log (1.8\times 10^{-5})=4.74

[NH_4Cl]=\frac{0.006}{0.035}

[NH_3]=\frac{0.004}{0.035}

pOH = ?

Putting values in above equation, we get:

pOH=4.74+\log(\frac{0.006/0.035}{0.004/0.035})\\\\pOH=4.92

To calculate pH of the solution, we use the equation:

pH+pOH=14\\pH=14-4.92=9.08

Hence, the pH of the solution is 9.08

3 0
3 years ago
Which of the following is not true about chemical changes? a. They form a new substance. b. They can be reversed by physical cha
Sonbull [250]

Answer: The correct option is b.

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Indicators showing chemical changes are :

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From the given information above, it can be stated that the correct option is b.

8 0
3 years ago
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Liula [17]

<u>Answer:</u> The volume of solution is 1.13 L

<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

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Given mass of silver nitrate = 400. g

Molar mass of silver nitrate = 170 g/mol

Putting values in above equation, we get:

2.09M=\frac{400}{170\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{400}{170\times 2.09}=1.13L

Hence, the volume of solution is 1.13 L

4 0
3 years ago
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