Answer : The correct option is, (D) CO₂, BCl₃, and Fe³⁺
Explanation :
According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.
(a) 
It is a Lewis-acid because it can accepts electron pairs.
(b) 
It is not a Lewis-acid because it can not accepts electron pairs but it is a base because it can donates and accept hydrogen ion.
(c) 
It is a Lewis-acid because it can accepts electron pairs because it has an incomplete octet and an empty 2p orbital.
(d) 
It is a Lewis-acid because it can accepts electron pairs.
Hence, the ions which behave as Lewis acids are, CO₂, BCl₃, and Fe³⁺
Answer:
2.5 %
Explanation:
Considering:
Or,
Given :
For
:
Molarity = 0.2850 M
Volume = 63.30 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 63.30 × 10⁻³ L
Thus, moles of
:
Moles of
= 0.0180405 moles
Moles of
= Moles of 
Thus, Moles of
= 0.0180405 moles
Molar mass of
= 35.453 g/mol
Mass = Moles * Molar mass = 0.0180405 moles * 35.453 g/mol = 0.6396 g
Volume of sea water = 25.00 mL
Density = 1.024 g/mL
Density = Mass / Volume
Mass = Density * Volume = 1.024 g/mL * 25.00 mL = 25.6 g
<u>Mass percent of Cl⁻ = 2.5 %</u>
Chemical indicators are the chemical reagents that show the change in reaction by changing color. Chemical indicators must be chosen with a narrow pH range.
<h3>What are indicators?</h3>
Indicators are the solutions or the substances used for the qualitative and the quantitative measurement by a change in color because of the absence or the presence of the sample concentration.
The chemical indicators cannot detect the exact pH and should be used with a narrow range of pH.
Therefore, option C. the narrow range of pH is the disadvantage of chemical indicators.
Learn more about chemical indicators here:
brainly.com/question/15114406
Expression for the Balmer series to find the wavelength of the spectral line is as follows:
1 / λ = R

Where, λ is wavelength, R is Rydberg constant, and n is integral value (4 here → Fourth level)
Substitute 1.097 x 10⁷ m⁻¹ for R and 4 for n in the above equation
1 / λ = (1.097 x 10⁷ m⁻¹)
= 0.20568 x 10⁷ m⁻¹
λ = 4.86 x 10⁻⁷ m
since 1 m = 10⁹ nm
λ = 486 nm