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antiseptic1488 [7]
3 years ago
10

A certain experimental mathematics program was tried out in 2 classes in each of 32 elementary schools and involved 37 teachers.

Each of the classes had 1 teacher and each of the teachers taught at least 1, but not more than 3, of the classes. If the number of teachers who taught 3 classes is n, then the least and greatest possible values of n, respectively, are
A) 0 and 13
B) 0 and 14
C) 1 and 10
D) 1 and 9
E) 2 and 8
Mathematics
1 answer:
zheka24 [161]3 years ago
6 0

Answer:

A) 0 and 13

Step-by-step explanation:

64 - 37 = 27

27/2 = 13.5

13 teachers can teach 3 classes at max

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A migraine sufferer took Two 400mg doses of naproxen. The half-life for
12345 [234]

Answer:

If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).

Then at t = 20:

y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}

Step-by-step explanation:

7 0
3 years ago
Pls help it’s due today
IgorLugansk [536]

Answer: y = 2/1x + 2

Step-by-step explanation:

A slope of 2 means rising 2 and run 1 on a graph. This would make x = 2/1. The + 2 allows the line to pass through (0,2) and therefore it will also pass through (-2,-2).

4 0
3 years ago
Please help!
ella [17]

Answer:

y = x + 5          

Step-by-step explanation:

1) First, find the slope of the line x-y = 4. We can do this by setting it up in slope-intercept form, represented by the equation y = mx + b. Whatever m or the coefficient of the x-term is will be the slope. Isolate y in the equation:

x-y = 4\\-y = -x+4\\y = x -4

So, the slope of the given equation is 1. Parallel lines share the same slope, thus the slope of the new line will be 1 as well.

2) Now, use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. Substitute values for m, x_1, and y_1 in the formula.

Since m is the slope, substitute 1 for it. Since x_1 and y_1 represent the x and y values of one point the line passes through, substitute the x and y values of (-6, -1) into those places as well. Then, isolate y in the resulting equation to put the equation in slope-intercept form and find the answer:  

y-(-1) = 1 (x-(-6))\\y + 1 = 1 (x + 6)\\y + 1 = x + 6\\y = x + 5

7 0
2 years ago
Find all solutions to the equation (x² + 5x + 6)(x² − 3x − 4) = 0.
Soloha48 [4]

Answer:

The solutions are:

x=-2,\:x=-3,\:x=-1,\:x=4

Step-by-step explanation:

To find the solutions to the equation \left(x^2+5x+6\right)\left(x^2-3x-4\right)=0 you need to:

  • Factor \left(x^2+5x+6\right)

Break the expression into groups

x^2+5x+6=\left(x^2+2x\right)+\left(3x+6\right)

Factor out x from (x^2+2x)

x^2+2x=x\left(x+2\right)

Factor out 3 from 3x+6

3x+6=3\left(x+2\right)

x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)

  • Factor \left(x^2-3x-4\right)

x^2-3x-4=\left(x^2+x\right)+\left(-4x-4\right)\\\\x^2-3x-4=x\left(x+1\right)-4\left(x+1\right)\\\\x^2-3x-4=\left(x+1\right)\left(x-4\right)

Therefore

\left(x^2+5x+6\right)\left(x^2-3x-4\right)=\left(x+2\right)\left(x+3\right)\left(x+1\right)\left(x-4\right)=0

Using the Zero Factor Theorem:

5 0
3 years ago
Can someone help me with this please
pogonyaev

Answer:

-1.5 is the gradient (m), correct equation: y= -1.5x-7

Step-by-step explanation:

m=y2-y1/x2-x1

for getting the correct equation, input y, x and m in the equation y=mx+c to find c

7 0
3 years ago
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