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Zinaida [17]
3 years ago
12

Please help and explain!

Mathematics
1 answer:
Scrat [10]3 years ago
5 0
K is the slope of the line formed by connecting the points.
Use slope formula:
\frac{y_2 - y_1}{x_2 - x_1}
where the 2 points are the end points of the line (First and last going Left to right)
(x_1,y_1) = (2,7)  \\ (x_2,y_2) = (8,28)
Substitute into slope formula
k= \frac{28-7}{8-2} = \frac{21}{6} = \frac{7}{2}
You can check if this is correct by going back to graph and going "up 7" and "over 2" to get from one point to the next.
You might be interested in
Tacoma's population in 2000 was about 200 thousand, and has been growing by about 8% each year. If this continues, what will Tac
Brums [2.3K]

Answer: The population will be 408,000 people.

Step-by-step explanation:

So in 2000 there were 200,000 people and it started to grow 8% every year so up to 2013.

so find 8% of 200,000 and then multiply it by the  the number of years.

8% * 200,000 =  16,000

Find the difference between the years.

2013 - 2000 = 13 years

13 * 16000 = 208000  This is the amount of new people from 2000 to 2013 so add it to the original population.

208,000 + 200,000 = 408,000  

5 0
3 years ago
What is the equation of the line passing through the points (Two-fifths, StartFraction 19 Over 20 EndFraction) and (one-third, S
Neporo4naja [7]

Answer:

  y = one-half x + three-fourths

Step-by-step explanation:

The 2-point form of the equation of a line can be used for starters.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values

  y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little

  y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...

  y = 1/2x -4/20 +19/20

  y = 1/2x +15/20

  y = 1/2x +3/4 . . . . line in slope-intercept form

8 0
3 years ago
Read 2 more answers
Two kinds of crated cargo, A and B, are to be shipped by truck. Each crate of cargo A is 50 cubic feet in volume and weighs 200
BlackZzzverrR [31]

Answer:

The correct answer is option b)

50a+10b<1000; 200a+360b < 7200; a> 0; b>0

Step-by-step explanation:

We are given that Two kind of crated cargo namely A and B to be shipped by truck.

<u>Cargo A:</u>

Volume of each crate of cargo A = 50 cubic ft

Weight of each crate of cargo A = 200 pounds

Let number of crates of cargo A to be shipped = a

Total volume of 'a' crates of cargo A = 50a cubic ft

Total weight of 'a' crates of cargo A = 200a pounds

<u>Cargo B:</u>

Volume of each crate of cargo B = 10 cubic ft

Weight of each crate of cargo B = 360 pounds

Let number of crates of cargo B to be shipped = b

Total volume of 'b' crates of cargo B = 10b cubic ft

Total weight of 'b' crates of cargo B = 360b

Total volume allowed in the truck is 1000 cubic ft

Total volume of 'a' crates of Cargo A and Total volume of 'b' crates of Cargo B = 50a+10b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

50a+10b ....... (1)

Total weight allowed (load limit) in the truck is 7200 pounds

Total weight of 'a' crates of Cargo A and Total weight of 'b' crates of Cargo B = 200a+360b cubic ft (This sum should be less than volume of truck so that it can fit in the truck)

So, the inequality becomes

200a+360b ....... (1)

And number of crates of cargo A and B are always a positive number.

So, a > 0 and b > 0.

So, the correct answer is option b.

<em>b. 50a+10b<1000; 200a+360b < 7200; a> 0; b>0</em>

3 0
3 years ago
Given the similarity statement<br> AJKL ANOP, what's the<br> corresponding side of ON ?
levacccp [35]

Answer:

ON = KJ

Step-by-step explanation:

JKL = NOP

We know the angles match

<J = <N

<K = <O

< L = <P

And we know

JK = NO

KL =  OP

JL = NP

We are looking for ON = KJ

5 0
3 years ago
Read 2 more answers
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
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