Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Answer:
125
Step-by-step explanation:
divide both sides of the equation by 0.8
0.8÷0.8=0.8÷100
any expression divided by 1 is itself
x=100÷0.8
divide the numbers
100÷0.8=125
125 is your answer
Answer:
A=2(wl+hl+hw)=2·(8·12+4·12+4·8)=352
Step-by-step explanation:
brainliest?
Most likely B because one pound is equal to 6 dollars. So i think it would be x= 1 and y= 6
So put the x as the dom and 6 as the num?
