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Maslowich
3 years ago
10

How many protons and neutrons are in the following isotope radium-226

Chemistry
1 answer:
8_murik_8 [283]3 years ago
8 0

Protons= 88

Neutrons= 138.

The weight of an element is comprised of entirely protons and neutrons. To get the protons look at the atomic number on the periodic table (88) and those are your protons. To get the neutrons take the weight of the isotope that you have and subtract the protons, giving you 138.

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Bezzdna [24]
Molar mass of Sodium Carbonate is 106, molarity is 1.0M. Seriously just look at a periodic table this is easy stuff.
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According to the periodic table, carbon has an atomic mass of 12.011 u. This indicates that the most abundant isotope of carbon
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The most abundant of all of the isotopes of an element will be the one who's mass the mass of element is closest to. In this case, the mass of atomic carbon is closest to the mass of carbon-12.
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How to I make a strength potion?
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Answer:

Hopefully this helps!

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4 0
3 years ago
What is the new mass/volume percent (m/v) of a KOH solution that is prepared by diluting 110 mL of a 6.0% (m/v) KOH solution to
denis-greek [22]

Answer:

The new mass/volume percent is 2.0% (m/v)

Explanation:

Dilution is a procedure by which the concentration of a solution is decreased, generally with the addition of a diluent. In other words, dilution is a process in which a concentrated solution is always started, to which a greater volume of solvent is added, causing the concentration and volume of the resulting solution to change. But the amount of solute used to prepare the initial solution remains the same.

The calculation of a dilution is made by:

Cinitial. Vinitial = Cfinal. Vfinal

where C indicates concentration and V indicates volume.

In this case:

  • Cinitial: 6.0% (m/v)
  • Vinitial: 110 mL
  • Cfinal: ?
  • Vfinal: 330 mL

Replacing:

6.0% (m/v) * 110 mL= Cfinal* 330 mL

Solving:

Cfinal=\frac{ 6.0 (m/v)*110 mL}{330 mL}

Cfinal=   2.0% (m/v)

<u><em>The new mass/volume percent is 2.0% (m/v)</em></u>

4 0
3 years ago
A sample of hydrogen has an initial temperature of 50.°
Lena [83]
Using the 
V1/T1=V2/T2
where
T1=50C= 323.15K
T2= -5C=268.15 K
V2= 212m^3
substitute the given values, we will get the initial volume
V1=V2T1/T2
V1= 255.48m^3

The initial volume is 255.48m^3




6 0
3 years ago
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