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2 years ago

5

A birthday cake is being made using a cylindrical baking pan. The radius of the pan is 4 inches, and the height is 5 inches whic

h formula represents the correct way to calculate the volume of the cake

2 answers:

Aleonysh [2.5K]2 years ago

6 0

Answer:

This formula:

Cylinder Volume = π • r² • height

Volume = PI * 4 ^2 * 5

Volume = PI * 16 * 5

Volume = 251.327412 cubic inches

Step-by-step explanation:

beks73 [17]2 years ago

6 0

Answer:

This formula:

Cylinder Volume = π • r² • height

Volume = PI * 4 ^2 * 5

Volume = PI * 16 * 5

Volume = 251.327412 cubic inches

Step-by-step explanation:

You might be interested in

A student moves into a bigger apartment that rents for $550 per month. That rent is $300 less than twice what she had been payin

Nataly_w [17]

Answer:

Step-by-step explanation:

Her former rent is $ x

Twice the former rent: 2*x = 2x

$300 less than 2x: 2x - 300

2x - 300 = 550

Add 300 to both sides

2x - 300 + 300 = 550 + 300

2x = 850

Divide both sides by 2

2x/2 = 850/2

x = 425

Her former rent = $425

8 0

3 years ago

Read 2 more answers

svet-max [94.6K]

Answer is D:
e + 5 = 3e - 11

2e = 16
e = 8

Ella is 8 years old
Jamie is 8+5 = 13 years old

6 0

2 years ago

Where in the world would we use this number 3.246

Zepler [3.9K]

In math and and other types of school stuff :) if that's what your asked

8 0

3 years ago

Find the percent of increase to the nearest whole from 12 to 20

ankoles [38]

Answer:

The answer is

<h2> $67\%$ </h2>

Step-by-step explanation:

To find the percentage increase we use the formula

<h3> $Percentage \: change = \frac{change}{original \: \: quantity} \times 100\%$ </h3>

From the question

The original value = 12

To find the change we subtract the smaller value from the larger one

That's

Change = 20 - 12 = 8

So the percentage increase is

<h3> $\frac{8}{12} \times 100 \%\\ = \frac{2}{3} \times 100\% \\ = 66.67\%$ </h3>

We have the final answer as

$67\%$ to the nearest whole number

Hope this helps you

3 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

2 years ago