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ololo11 [35]
3 years ago
10

The Greek letter D stands for

Chemistry
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:d

Explanation:

Deffense [45]3 years ago
6 0
C because D stands for delta therefore it signifies change
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In a gravimetric analysis, if the water molecules are not completely removed from the salt during the heating process, will the
sashaice [31]
<span>Presumably, any salt-to-water ratio would be low, if the water molecules are not removed from the solution, whatever it may be, as salt is typically a very small potion in saline water.</span>
5 0
3 years ago
A certain reaction has an enthalpy of Δ=44 kJ and an activation energy of a=61 kJ. What is the activation energy of the reverse
avanturin [10]

Answer:

E = 17 kJ

Explanation:

The enthalpy of the reaction is:

\Delta H = E_{p} - E_{r}  

<u>Where</u>:

Ep: is the energy of the products

Er: is the energy of the reactants

Similarly, the enthalpy of the reaction is related to the activation energy forward (E_{F}) and to the activation energy reverse (E_{R}) as follows:

\Delta H = E_{F} - E_{R}  

Having that ΔH = 44 kJ and E_{F} = 61 kJ, the activation energy of the reverse reaction is:

E_{R} = E_{F} - \Delta H = 61 kJ - 44 kJ = 17 kJ  

Therefore, the activation energy of the reverse reaction is 17 kJ.

I hope it helps you!

3 0
3 years ago
How many moles of copper would be needed to make one mole of cu2o?
julia-pushkina [17]

Answer:

Explanation:

You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.

5 0
3 years ago
Determine the empirical formula of a compound containing 48.38 grams of carbon, 8.12 grams of hydrogen, and 53.5 grams of oxygen
gogolik [260]

Answer:

Empirical formula = CH2O

Molecular formula = C6H12O6

Explanation:

According to this question, a compound is said to contain the following: 48.38g Carbon, 8.12g H, and 53.5g O.

First, we divide each mass value by its molar mass to convert to a mole value;

C = 48.38g ÷ 12g/mol = 4.03mol

H = 8.12g ÷ 1g/mol = 8.12mol

O = 53.5g ÷ 16g/mol = 3.34mol

Next, we divide each mole value by the lowest value (3.34mol)

C = 4.03mol ÷ 3.34 = 1.21

H = 8.12mol ÷ 3.34 = 2.43

O = 3.34mol ÷ 3.34 = 1

Approximately, the empirical ratio of CHO = 1:2:1, hence, the empirical formula is CH2O.

2. If the molar mass of the compound was determined to be 180.15 g/mol.

C = 12, H = 1, O = 16

(CH2O)n = 180.15

{12 + 1(2) + 16}n = 180.15

(12 + 2 + 16)n = 180.15

(30)n = 180.15

n = 180.15 ÷ 30

n = 6.005

Hence, (CH2O)n = (CH2O)6

Molecular formula = C6H12O6

3 0
3 years ago
Calculate the mass of butane needed to produce 46.4 g of carbon dioxide
Alenkinab [10]
Molar mass:

CH₄ = 12 + 1 x 4 = 16.0 g/mol

CO₂ = 12 + 16 x 2 = 44.0 g/mol

Balanced <span>equation :
</span>
<span>CH</span>₄<span> + 2 O</span>₂<span> = CO</span>₂<span> + 2 H</span>₂<span>O
</span>
16.0 g CH₄ --------------- 44.0 g CO₂
(mass of CH₄) ----------- 46.4 g CO₂

mass of CH₄ = 46.4 x 16.0 / 44.0

mass of CH₄ = 742.4 / 44.0

= 16.87 g CH₄

hope this helps!
8 0
3 years ago
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