What is polarity as used in magnets?

Chemistry

2 answers:

uysha [10]3 years ago

8 0

Answer:

The polarity of a magnet usually means the direction of a vector which points from the south pole of the magnet toward the north pole. ... In this case the polarity is expressed in a way that indicates a circular direction, such as clockwise, or as a perpendicular vector representing the curl of the internal field.

Explanation:

Oduvanchick [21]3 years ago

6 0

In a permanent magnet, a magnetic field is produced by the composite motions of electrons in geometrically aligned atoms.

A magnetic field is characterized by poles called north and south. Magnetic polarity refers to the orientation of these poles in space.

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When a substance like sugar dissolves in water, the particles intermingle. This is possible because the particles of sugar

lozanna [386]

Answer:

Explanation:

3 0

3 years ago

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig

BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HgO: 2 moles
Hg: 2 moles
O₂: 1 moles

The molar mass of the compounds is:

HgO: 216.59 g/mole
Hg: 200.59 g/mole
O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles× 216.59 g/mole= 433.18 grams
Hg: 2 moles× 200.59 g/mole= 401.18 grams
O₂: 1 mole× 32 g/mole= 32 grams

Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

$moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}$