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Norma-Jean [14]
4 years ago
7

How many orbital blocks are represented in this periodic table?

Chemistry
2 answers:
dmitriy555 [2]4 years ago
7 0

Answer:

4

Explanation:

marissa [1.9K]4 years ago
4 0

Answer:

The answer is 4 on edge

Explanation:

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What evidence did dalton have that atoms actually exist?
likoan [24]
<span>Dalton noted that the chromium oxide molecules that he was studying had masses of oxygen that were not the same: he found that there were constant ratios to these mass differences, however, so there had to be some sort of "units" (atoms) making up the ratios of these particles.</span>
5 0
3 years ago
Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
Ugo [173]

0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.

Explanation:

Data given:

Volume of the base = 47 ml

molarity of the base= 0.39 M

volume of the acid = 25 ml

molarity of the acid =?

For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined.  The formula used:

Macid X Vacid = Vbase x Mbase

Macid = \frac{Vbase X M base}{V acid}

putting the values given in the rearranged equation above:

Macid = \frac{0.39 x47}{25}

           = 0.73 M

The concentration of the sulphuric acid needed is 0.73 M.

3 0
4 years ago
If 12.1 kilograms of al2o3(s), 60.4 kilograms of naoh(l), and 60.4 kilograms of hf(g) react completely, how many kilograms of cr
Fynjy0 [20]
Answer is: 7,826 kg of cryolite.
Chemical reaction: Al₂O₃ + 6NaOH + 12HF → 2Na₃AlF₆ + 9H₂<span>O.
m(</span>Al₂O₃) = 12,1 kg = 12100 g.
n(Al₂O₃) = m(Al₂O₃) ÷ M(Al₂O₃).
n(Al₂O₃) = 12100 g ÷ 101,96 g/mol = 111,86 mol; limiting reactant.
m(NaOH) = 60,4 kg = 60400 g.
n(NaOH) = 60400 g ÷ 40 g/mol.
n(NaOH) = 1510 mol.
m(HF) = 60,4 kg = 60400 g.
n(HF) = 60400 g ÷ 20 g/mol = 3020 mol.
From chemical reaction: n(Al₂O₃) : n(Na₃AlF₆) = 6 : 2.
n(Na₃AlF₆) = 2 ·111,86 mol ÷ 6 = 37,28 mol.
m(Na₃AlF₆) = 37,28 mol · 209,94 g/mol.
m(Na₃AlF₆) = 7826,56 g = 7,826 kg.
7 0
4 years ago
Describe the relationship between the mole and molar mass. Be prepared to describe the process for converting between moles and
malfutka [58]

Answer:

The molar mass of any substance is the mass in grams of one mole of representative particles of that substance. ... In such a conversion, we use the molar mass of a substance as a conversion factor to convert mole units into mass units (or, conversely, mass units into mole units).

Explanation:

8 0
3 years ago
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Which process causes earth surface to warm
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Air production process
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