Answer:
I believe it is 2 (6x^2 y^2 + xy-1
Step-by-step explanation:
x = y + 4 is already done so we will substitute that into the other equation!
3(y + 4) + y = 16
Distribute.
3y + 12 + y = 16
Add the terms.
4y + 12 = 16
Give y its own side.
4y = 4
Divide by 4.
y = 1
Substitute this back into one of the equations.
x = 1 + 4
x = 5
The point for these 2 equations is (5, 1)
⭐ Answered by Hyperrspace (Ace) ⭐
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Given: y = 2x^2 - 32x + 56
1) y = 2 [ x^2 - 16x] + 56
2) y = 2 [ (x - 8)^2 - 64 ] + 56
3) y = 2 (x - 8)^2 - 128 + 56
4) y = 2 (x - 8)^2 - 72 <----------- answer
Minimum = vertex = (h,k) = (8, - 72)
=> x-ccordinate of the minimum = 8 <-------- answer
Answer:
4x-2
Step-by-step explanation:
hope this helps
9514 1404 393
Answer:
150°
Step-by-step explanation:
The rule here is that the external angle is half the difference of the arcs subtended. That relation is used to form an equation, which can then be solved for whatever measure is of interest.
(RB -EC)/2 = D
((13x +7) -(60))/2 = (5x -10)
13x -53 = 10x -20 . . . . . . . . . . multiply by 2
3x = 33 . . . . . . . . . . . . . . add 53-10x to both sides
x = 11 . . . . . . . . . . . . divide by 3
RB = 13x +7 = 13·11 +7 = 150
The measure of arc RB is 150°.