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Anastaziya [24]
4 years ago
13

What amount needs to be invested today at 6% simple interest in order to have $4000 in 2 years?

Business
1 answer:
garri49 [273]4 years ago
4 0
Data:
A (amount) = ?
P (Principal) = $ 4000
r (rate) = 6% → 0.06
t (time) = 2 years

Formula:
A = P(1+r*t)

Solving:
A = P(1+r*t)
A = 4000(1+0.06*2)
A = 4000(1+0.12)
A = 4000*1.12
\boxed{\boxed{A = \$\:4480}}\end{array}}\qquad\quad\checkmark


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Please check the answer section.

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The correct option is these statements are true

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