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Alenkinab [10]
3 years ago
7

From her house, Haley could drive due north to get to her parents' house or she could drive due east to get to her grandparents'

house. It is 7 kilometers from Haley's house to her parents' house and a straight-line distance of 9 kilometers from her parents' house to her grandparents' house. How far is Haley from her grandparents' house? If necessary, round to the nearest tenth. Please help me with this phytagareon theorem question please. I would really appreciate it . Please asap
Mathematics
1 answer:
vivado [14]3 years ago
5 0

Answer:

5.7km

Step-by-step explanation:

-let the drive east be the base of our 'triangle' and the drive north be the height, h.

-The distance from the parents to the grandparents, 9km, forms the hypotenuse.

#Using Pythagorean Theorem, we can find the distance to her grandparents as:

H^2=h^2+b^2\\\\9^2=7^2+b^2\\\\b^2=81-49\\\\b=\sqrt{32}\\\\=5.657\approx5.7\ km

Hence, the distance fro Hayley's place to her grandparents is 5.7km

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Step-by-step explanation:

3 0
3 years ago
Joey is 5 feet tall and casts a 45-foot shadow. A building casts a 270-foot shadow at the same time. How tall is the building?
Cerrena [4.2K]

Answer:

the building is thirty feet tall

Step-by-step explanation:

so make a ratio of shadow to joey

5:45

simplify that to

1:9

so you can now divide 270 by nine

30

the building is thirty feet tall

5 0
3 years ago
If x represents a number, then write an expression for one half the sum of x and 7.
Lostsunrise [7]

Answer:

1/2(x+7)

Step-by-step explanation:

4 0
3 years ago
Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).
lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted C, which we can parameterize by the vector-valued function,

\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)

for 0\le t\le1, which has differential

\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt

Then with x(t)=y(t)=z(t)=1-t, we have

\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r

=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt

\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt

Complete the square in the quadratic term of the integrand: t^2-2t+2=(t-1)^2+1=(1-t)^2+1, then in the integral we substitute u=1-t:

\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt

\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du

Make another substitution of v=u^2:

\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv

Integrate by parts, taking

r=v+1\implies\mathrm dr=\mathrm dv

\mathrm ds=e^v\,\mathrm dv\implies s=e^v

\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv

\displaystyle=-(2e-1)+(e-1)=-e

So, we have by the fundamental theorem of calculus that

\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)

\implies-e=f(1,1,1)-2

\implies f(1,1,1)=2-e

3 0
3 years ago
How do you divide (n^2-n-29)/(n-6) ??
Orlov [11]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Polynomial long division is done the way any long division is done. Find a "partial quotient", subtract from the dividend the product of that partial quotient and the divisor. The result is a new dividend. Repeat until the degree of the dividend is less than that of the divisor.

__

In the attached, the "Hints" show you how the partial quotient is found, and they show you how the product of the partial quotient and divisor is found.

The partial quotient term is simply the ratio of the highest degree terms of dividend and divisor. (Unlike numerical long division, there is no guessing.)

__

The remainder is the dividend of lower degree than the divisor. As in numerical long division, the full quotient expresses the remainder over the divisor.

For example, 5 ÷ 3 = 1 r 2 = 1 + 2/3.

Your full quotient is (n+5) +1/(n-6).

5 0
2 years ago
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