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vodomira [7]
3 years ago
10

How many combinations without repetition are possible if n = 5 and r = 3?

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

_nC_r=\dfrac{n!}{r!(n-r)!}\\\\_5C_3=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10

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