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Lunna [17]
3 years ago
7

The label shows nutritional benefits for an entire 12-fluid-ounce sports drink. The beverage company wants to produce a 16-fluid

-ounce bottle of the same drink.
The 12 oz drink has 120 calories and 24grams of carbohydrates.

How many calories and grams (g) of carbohydrates should the company put on the 16oz nutrition-facts label?
Mathematics
1 answer:
RUDIKE [14]3 years ago
8 0

Answer:

160 calories and 32 grams of carbohydrates

Step-by-step explanation:

You first find the calories and carbohydrates per ounce.

120 / 12 = 10 calories per ounce

24 / 12 = 2 grams of carbohydrates per ounce

You then multiply these by the new number of ounces

16 x 10 = 160 calories

16 x 2 = 32 grams of carbohydrates

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spin [16.1K]

Answer:

27 pages

Step-by-step explanation:

Since you read 3 pages on Monday and you read 3 times that number on Tuesday, the equation should be 3*3 to equal 9. Then, since you read 9 pages on Tuesday and 3 times that number on Wednesday, the equation should be 9*3 to equal 27 pages. So, on Wednesday, you read 27 pages in total.

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3 years ago
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Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
A ray that contains a point that is equidistant from both sides of the angle. *
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12 + 4x &gt; 24 or 10 - 12x &gt; 22
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Which statements are true about the trigonometric ratios of this triangle​
rosijanka [135]

Answer:

Options (1), (2), (3) and (4)

Step-by-step explanation:

By applying the sine and cosine rules in the given triangle,

sinθ = \frac{\text{Opposite side}}{\text{Hypotenuse}}

cosθ = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

cos(30°) = \frac{AC}{AB}

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sin(30°) = \frac{BC}{AB}

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             = \frac{1}{2}

cos(60°) = \frac{BC}{AB}

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              = \frac{1}{2}

sin(60°) = = \frac{AC}{AB}

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              = \frac{\sqrt{3}}{2}

Options (1), (2), (3) and (4) are the correct options.

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