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3 years ago

5+4*4 divided by 2-3 whole solution pls

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

7 0

Answer:

Step-by-step explanation:

PEMDAS

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

5+4*4/2-3

5+4=9

9*4/2-3

Multiply and divide from left to right.

9*4=36

36/2-3

36/2=13

13-3=10

10 is the correct answers.

Airida [17]3 years ago

7 0

Answer:

can you help me please i need help

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Given that f(x)= 2x+1 and g(x)= x^2 +2x+1 find (F+g)(2). Find (F.g)(x) find f(x)/g find f(2) +g(-2)?

Pepsi [2]

Answer:

$(f+g)(2) = 14$

$f(g(x)) = 2x^2 + 4x +3$

$\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}$

$f(2) + g(-2) = 6$

Step-by-step explanation:

Function composition and transformation combines functions together using operations such as addition, subtraction, multiplication, division and substitution. To find each, perform the operation with the functions f(x) = 2x+1 and $g(x) = x^2 + 2x +1$ .

(f+g)(x) is the functions f and g added together with 2 substituted for x.

$(f+g)(x) = 2x+1 + x^2 +2x + 1 = x^2 + 4x + 2\\(f+g)(2) = 2^2 + 4(2) + 2 = 14$

(f·g)(x) is function composition that means f(g(x)) or substitute g(x) into f(x).

$f(g(x)) = 2(x^2+2x+1)+1 = 2x^2 + 4x+2 + 1\\f(g(x)) = 2x^2 + 4x +3$

f(x) / g(x) is division of the two functions. Division can only occur with polynomials if they share the same factors or things which multiply to create them. If none are present, do not simplify.

$\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}$

This cannot be simplified.

f(2) + g(-2) means find the function value of f at 2 and the function value of g at -2 then add them together.

$f(2)+g(-2) = 2(2)+1 + ((-2)^2+2(-2) + 1)\\f(2) + g(-2) = 5 + (4-4+1)\\f(2) + g(-2) = 5 +1 = 6$

7 0

3 years ago

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What is the answer to this problem -69=7v-6

alex41 [277]

-69= 7v-6 so v equals 74 or something

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3 years ago

During the 7th examination of the Offspring cohort in the Framingham Heart Study, there were 1219 participants being treated for

AlexFokin [52]

Answer:

95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

Step-by-step explanation:

We are given that during the 7th examination of the Offspring cohort in the Framing ham Heart Study, there were 1219 participants being treated for hypertension and 2,313 who were not on treatment.

The sample proportion is : $\hat p$ = x/n = 1219/3532 = 0.345

Firstly, the pivotal quantity for 95% confidence interval for the proportion of the population is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.345

n = sample of participants = 3532

p = population proportion

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level of

significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p= [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.345-1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ , $0.345+1.96 \times {\sqrt{\frac{0.345(1-0.345)}{3532} } }$ ]

= [0.3293 , 0.3607]

Hence, 95% confidence interval for the proportion of the population which are on treatment is [0.3293 , 0.3607].

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3 years ago

Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is

Lerok [7]

Answer: possible values of Range will be values that are >=91 or <=998

Step-by-step explanation:

Given that :

Set Q contains 20 positive integer values. The smallest value in Set Q is a single digit value and the largest value in Set Q is a three digit value.

Therefore,

given that the smallest value in set Q is a one digit number :

Then lower unit = 1, upper unit = 9( this represents the lowest and highest one digit number)

Also, the largest value in Set Q is a three digit value:

Then lower unit = 100, upper unit = 999 ( this represents the lowest and highest 3 digit numbers).

Therefore, the possible values of the range in SET Q:

The maximum possible range of the values in set Q = (Highest possible three digit value - lowest possible one digit) = (999 - 1) = 998

The least possible range of values in set Q = (lowest possible three digit value - highest possible one digit value) = (100 - 9) = 91

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3 years ago

T-5-2t+5 simplify expression

pav-90 [236]

Answer:

-t

Step-by-step explanation:

t - 5 - 2t + 5 =

t - 5 + 5 - 2t =

t - 2t =

-t

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3 years ago

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