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2 years ago

Which quadrilaterals appear tohave 2 pairs of opposite sides that are parallel?

Mathematics

1 answer:

topjm [15]2 years ago

4 0

Answer: A and B

Step-by-step explanation:

A square has two sets of parallel sides and so does a parallelogram.

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Please help me with this I will mark brainlist if you answer correctly. (I will know if you answer correctly or not)

lukranit [14]

Answer:

18/5

Step-by-step explanation:

6 0

3 years ago

Christine went shopping and bought each of her ten nephews a gift, either a video costing $14.95 or a cd costing $16.88. she spe

JulsSmile [24]

She got 9 videos, and 1 cd.

7 0

3 years ago

Calculate.<br> 1) 4 x (3 divided by 8 + 1)

grin007 [14]

4(3/(8+1) = 4(3/9) = 12/9 = 4/3

4((3/8)+1) = 4(11/8) = 44/8 = 11/2

just depends on which way the equation is written

5 0

3 years ago

Someone please help me!!

Phoenix [80]

Answer:

x=6

UV=40

WV=40

UW=30

Step-by-step explanation:

GIVEN UV=WV

6X+4=40

X=6

NOW PUT X=6 in WV AND UW

6 0

3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

2 years ago