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Scilla [17]
4 years ago
12

If a resident accidentally causes a chunk of ice to fall from the roof, how fast would the ice be moving when it hits the ground

? Neglect air resistance.
Physics
1 answer:
Elena L [17]4 years ago
5 0

Answer:

v = √2gh

v = 7 m / s

Explanation:

For this exercise we can use the law of conservation of energy

starting point. In the roof

         Em₀ = U = m g h

final point. On the floor

          Em_f = K = ½ m v²

 

as there is no friction, the energy is conserved

          Em₀ = Em_f

          m g h = ½ m v²

          v = √2gh

In the exercise the height of the ceiling is not indicated, but in general the height of the ceiling of a house is h = 2.5 m

         v = √ (2 9.8 2.5)

         v = 7 m / s

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The force of air resistance acts to oppose the motion of an object moving through the air. A ball is thrown upward and eventuall
ozzi

Answer:

For a (1) net force will be greater than the weight of the ball

For b (2) net force will be lesser than the weight of the ball

Explanation:

For (a):

For a linear motion of a system, one must have to understand, according to Newtons first law of motion, which is also known as law of inertia, a body which is at motion will continue to move or a body at rest will continue to rest until an external force is applied to it. In the given case, when ball goes upward, one thing is for sure, the net force is greater than the weight of the ball, because three forces are applied during upward motion:

gravity or weight which is pulling the ball downward,

air resistance, which is also acting downward as it is creating friction between ball and air molecules, so creating hindrance in upward motion

External force to throw ball upward

So

Net Force = Upward force - Air friction - Weight

Since ball is going upward, so net force is greater than both weight and air friction which are pulling ball downward.

For (b):

For a linear motion of a system, one must have to understand, according to Newtons first law of motion, which is also known as law of inertia, a body which is at motion will continue to move or a body at rest will continue to rest until an external force is applied to it. In the given case, when ball goes downward, one thing is for sure, the net force is lesser than the weight of the ball, because two forces are applied during downward motion:

gravity or weight which is pulling the ball downward,

air resistance, which is acting upward as it is creating friction between ball and air molecules, so creating hindrance in downward motion

So

Net Force = Weight - Air friction

Since ball is going downward, so weight is greater than net force which is in this case is air friction which is pulling ball upward.

4 0
4 years ago
Oil (SAE 30) at 15.6 oC flows steadily between fixed, horizontal, parallel plates. The pressure drop per unit length along the c
solong [7]

Answer:

q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s

Explanation:

For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as

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μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s

(ΔP/L) = 26 KPa/m = 26000 Pa/m

q = (2h³/3μ) (ΔP/L)

q = (26000) × (2(0.002³)/(3×0.38))

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5 0
3 years ago
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A system consists of a disk of mass 2.33 kg and radius 50 cm upon which is mounted an annular cylinder of mass 2.20 kg with inne
Gekata [30.6K]

Answer:

Kinetic energy of the system = 2547.41 Joules.

Explanation:

Given:

Disk:

Mass of the disk (m) = 2.33 kg

Radius of the disk (r) = 50 cm = \frac{50}{100} =0.5 m

Cylinder:

Mass of the annular cylinder (M) = 2.20 kg

Inner radius of the cylinder (R_i) = 0.2 m

Outer radius of the cylinder (R_o) = 0.3 m

The angular speed of the system (\omega) = 15.1 rev/s

Angular speed in in terms of Rad/sec = 15.1\times 2\pi =94.876 rad/sec

Formula to be used:

Rotational Kinetic energy, (KE)_r = \frac{I\times \omega^2}{2}

So, before that we have to work with the moment of inertia (MOI) of the system.

⇒ MOI of the system = MOI of the disk + MOI of the cylinder

⇒ MOI (system) = \frac{mr^2}{2} +\frac{M(R_i+R_o)^2}{2}

⇒ MOI (system) = \frac{2.33\times (0.5)^2}{2} + \frac{2.20\times (0.2+0.3)^2}{2}

⇒ MOI (system) = 0.566 kg.m^2

Now

The rotational Kinetic energy.

⇒ (KE)_r =\frac{I\omega^2}{2}

Plugging the values.

⇒  (KE)_r=\frac{0.566\times (94.876)^2}{2}

⇒ (KE)_r=2547.41 Joules

Then

The kinetic energy of the rotational system is 2547.41 J.

5 0
3 years ago
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