Question

6. How much heat is absorbed by a persons hand if 100 grams of liquid water at 100°C is poured on his hand? (Assume the final temperature of the water will be normal body temperature of 37°C)

Answer 1

The heat absorbed by a persons hand is 26,359.2 J.

Heat absorbed

The quantity of heat absorbed by the persons hand is heat gained or transferred from the hot water to cold hand. This is based on the principle of conservation of energy.

The quantity of heat absorbed is calculated as follows;

Q = mcΔθ

where;

• Q is the quantity of heat absorbed
• m is mass of the liquid
• Δθ is change in temperature

Q = 100 x 4.184 x (100 - 37)

Q = 26,359.2 J

Thus, the heat absorbed by a persons hand is 26,359.2 J.

Learn more about heat capacity here: brainly.com/question/16559442