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GuDViN [60]
3 years ago
9

Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so

me have more details available when you click on them. Drag and drop each label to the corresponding area it identifies in the image.

Physics
1 answer:
erica [24]3 years ago
5 0

1 - cytoplasm

2 - DNA

3 - rybosome

4 - cell membrane

5 - nucleus

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How can you see a unicellular organsim
Gnesinka [82]
Use a very very very powerful microscope...

5 0
3 years ago
-A 1000 kg car is rolling down the street at 2.5 m/s. How fast would a 1800 kg car have to collide into it in
Readme [11.4K]

1.39m/s

Explanation:

Given parameters:

Mass of car M₁ = 1000kg

Velocity V₁ = 2.5m/s

Mass of second car M₂ = 1800kg

Unknown:

Velocity of second car V₂ = ?

Solution:

For the other body to come to rest, the momentum of the colliding cars must be equal and in the opposite direction:

       Momentum of car 1 - momentum of car 2 = 0

 Momentum of car 1 = Momentum of car 2

  M₁V₁ = M₂V₂

The unknown is V₂

      1000x2.5 = 1800V₂

                  V₂ = \frac{2500}{1800} = 1.39m/s

Learn more:

Momentum brainly.com/question/2990238

#learnwithBrainly

3 0
3 years ago
If a box weighing 520 N is hung from a spring whose constant is 650 N/m, how many centimeters will the spring stretch?
lara [203]

80 cm

hope this helps :)

3 0
3 years ago
Read 2 more answers
Why is the law of gravity an example of a universal law?
Greeley [361]

Answer:

A

Explanation:

The most important part about this is not only that objects pull on each other, but that two objects attract each other with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. This is known as Newton's law of universal gravitation.

8 0
4 years ago
Read 2 more answers
At a distance of 41 ft , an ionizing radiation source delivers 5.0 rem of radiation. How close could you get to the source and s
mash [69]

Answer:

at distance 18.33 ft no biological effects

Explanation:

given data

distance = 41 ft

radiation = 5 rem

to find out

how close get so no biological effects

solution

we know here that intensity of radiation R is inversely proportional to (radiation)²

so here equation will be

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}   .............1

here I is intensity

so here I1 = 25

because for  0 to 25 there is  no detectable effects and for 25 to 100 it will . temporary decrease so

we take 25 because dose is less than 25 so we take that highest value

so

\frac{I1}{I2}  = (\frac{R2}{R1})^{2}

\frac{25}{5}  = (\frac{41}{R1})^{2}

R1 = 18.33 ft

so at distance 18.33 ft no biological effects

6 0
3 years ago
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