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son4ous [18]
4 years ago
6

Calculate the energy of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49 × 1014 hz.

Physics
1 answer:
Tcecarenko [31]4 years ago
8 0
The energy of a photon is given by
E=hf
where
h=6.6 \cdot 10^{-34} Js is the Planck constant
f is the frequency of the photon

In our problem, the frequency of the light is 
f=5.49 \cdot 10^{14}Hz
therefore we can use the previous equation to calculate the energy of each photon of the green light emitted by the lamp:
E=hf=(6.6 \cdot 10^{-34}Js)(5.49 \cdot 10^{14} Hz)=3.62 \cdot 10^{-19} J
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3 years ago
13.
lisov135 [29]

The net torque on the seesaw is 294 Nm.

<h3>What is torque?</h3>

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

  • τ = mgd-m'gd'........... Equation 1

Where:

  • τ = Net torque
  • m = Jenny's mass
  • m' = Tom's mass
  • d = Jenny's distance from the pivot
  • d' = Tom's distance from the pivot
  • g = acceleration due to gravity

From the question,

Given:

  • m = 40 kg
  • m' = 30 kg
  • d = 1.5 m
  • d' = 1 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • τ = (40×1.5×9.8)-(30×1×9.8)
  • τ  = 588-294
  • τ  = 294 Nm

Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

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3 years ago
Q66 what the answer plz help me I don’t understand this:(
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Answer:

C

Explanation:

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