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dezoksy [38]
3 years ago
5

What is reflection? Reflection is light that has struck a surface and has _______.

Physics
1 answer:
andrew11 [14]3 years ago
5 0
1.)bounced off...in pretty sure(sorry if wrong)
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What inflammatory molecule aids with muscle building and is released when muscles experience microscopic damage?
Reika [66]

Answer:

Cytokines

Explanation:

Cytokines are known as inflammatory molecules which are also proteinous and aid signaling of certain processes and conditions in the body.

They are also normally involved in aiding muscle building and are released when muscles experience microscopic damage which may lead to the muscles being sore.

3 0
2 years ago
What is the change in internal energy of the system (∆U) in a process in which 10 kJ of heat energy is absorbed by the system an
Trava [24]

Answer:

Explanation:

According to first law of thermodynamics:

∆U= q + w

= 10kj+(-70kJ)

-60kJ

, w = + 70 kJ

(work done on the system is positive)

q = -10kJ ( heat is given out, so negative)

∆U = -10 + (+70) = +60 kJ

Thus, the internal energy of the system decreases by 60 kJ.

8 0
3 years ago
How can the motion of an object that is NOT moving change?​
Semenov [28]
Only if a force acts upon it, it can move.
6 0
3 years ago
A sound source emits 20.0 W of acoustical power spread equally in all directions. The threshold of hearing is 1.0 × 10-12 W/m2.
ahrayia [7]

Answer:

0.0018 W/m²

Explanation:

Power and intensity are related as:

I=\frac{P}{4\pi r^2}

P=  20.0 W (given)

r = 30.0 m (given)

I=\frac{20.0}{4\pi(30.0)^2}=0.0018 W/m^2

Intensity in decibels:

I(dB)=10log\frac{I}{I_o}\\=10log\frac{0.0018}{10^{-12}}=92.5 dB

7 0
3 years ago
Problem 1 Observer A, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed
ANTONII [103]

Answer:

markers are 29.76 m far apart in the laboratory

Explanation:

Given the data in the question;

speed of particle = 0.624c

lifetime = 159 ns = 1.59 × 10⁻⁷ s

we know that; c is speed of light which is equal to 3 × 10⁸ m/s

we know that

distance = vt

or s = ut

so we substitute

distance = 0.624c × 1.59 × 10⁻⁷ s

distance = 0.624(3 × 10⁸ m/s) × 1.59 × 10⁻⁷ s

distance = 1.872 × 10⁸ m/s × 1.59 × 10⁻⁷ s

distance =  29.76 m

Therefore, markers are 29.76 m far apart in the laboratory

3 0
2 years ago
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