Arsenic is Element Number 33 ... it has 33 protons in its nucleus.
You're correct that the stable isotope of the atom is the one with
42 neutrons, for a total Atomic Weight of 75.
Atoms of Arsenic also exist with 41 neutrons and 40 neutrons
in their nucleus, but those are unstable.
The nucleus with 41 neutrons (Atomic Weight = 74) has a 50% chance
of falling apart and becoming a nucleus of Germanium within 80 days.
The nucleus with 40 neutrons (Atomic Weight = 73) has a 50% chance
of falling apart and becoming a nucleus of Germanium within 18 days.
Heat is technically the movement or more like vibration of the molecules. More thermal energy = more vibration
Answer:
Ranking the cars based on magnitude of momentum <em>(largest to smallest)</em>:
1. Purple, Light Blue
2. Red, Yellow, Blue
3. Green
Explanation:
Based on the given parameters ( mass and velocity), we can calculate the momentum of the various cars using the formula:
momentum = mass x velocity
1. Momentum of red car = 1000kg x 10m/s = 10,000Kgm/s
2. Momentum of Yellow car = 2000kg x 5m/s = 10,000Kgm/s
3. Momentum of blue car = 500kg x 20m/s = 10,000Kgm/s
4. Momentum of light blue car = 1000kg x 20m/s = 20,000Kgm/s
5. Momentum of green car = 500kg x 10m/s = 5,000Kgm/s
6. Momentum of purple car = 4000kg x 5m/s = 20,000Kgm/s
Hence,
Ranking the based on magnitude of momentum <em>(largest to smallest)</em> we have:
1. Purple, Light Blue
2. Red, Yellow, Blue
3. Green
An open ground mostly una park
Answer:
(1) 
(2) Diagram has been attached in the solution.
Explanation:
This question is from projectile motion.
From the given question, we will discuss the motion of the basket ball only in the vertical direction from which we will be able to find out the angle of the initial velocity with the horizontal with which it should be shoot to enter the hoop.
Part (1):
Let us assume:
= initial position of the basket ball = 2.1 m
= final position of the basket ball = 3.05 m
= acceleration of the ball along the vertical = 
= time taken to reach the goal = 0.8 s
= angle of the initial velocity with the horizontal
= initial speed of the ball = 7 m/s
= initial vertical velocity of the ball = u\sin \theta
Using the equation of motion for constant acceleration, we have
Hence, the angle of the shoot of the basket ball with the horizontal is such that it reaches the hoop on time.
Part (2):
For this part, a diagram has been attached.
