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nata0808 [166]
3 years ago
10

Need help with this one question!​

Physics
2 answers:
Lelu [443]3 years ago
8 0

Answer:

Actual Mechanical Advantage

Explanation:

AMA=mg/F(applied)

lisov135 [29]3 years ago
4 0
I think the following ratio is called, “actual mechanical advantage.”
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Suppose A=BnCm, where A has dimensions LT, B has dimensions L2T-1, and C has dimensions LT2. Then the exponents n and m have the
julsineya [31]

Explanation:

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A=B^nC^m\\\\\ [LT]=[L^2T^{-1}]^n[LT^2}]^m\\\\\ [LT]=L^{2n}T^{-n}L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}

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