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2 years ago

Need help with this one question!

Physics

2 answers:

Lelu [443]2 years ago

8 0

Answer:

Actual Mechanical Advantage

Explanation:

AMA=mg/F(applied)

lisov135 [29]2 years ago

4 0

I think the following ratio is called, “actual mechanical advantage.”

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The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?

larisa86 [58]

Answer:

$(a)255mm \\ (b)0.255m$

Explanation:

$(a)1cm = 10mm \\ 25.5cm = x$

Cross multiply

$1x = 25.5 \times 10 \\ x = 255mm$

$(b)100cm = 1m \\ 25.5cm = x$

cross multiply

$100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m$

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0

2 years ago

Read 2 more answers

Northrop aircraft developed and built a deceleration sled to test the effects of the extreme forces on humans and equipment. In

dolphi86 [110]

20 hours i think that what they do

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2 years ago

A triangular plate with a non-uniform areal density has a mass M=0.500 kg. It is suspended by a pivot at P and can oscillate as

malfutka [58]

The period of the oscillations.T = 1.2042s

Opposition is the process of any quantity or measure fluctuating repeatedly about its equilibrium value throughout time. This process is referred to as oscillation. Oscillation, a periodic fluctuation of a substance, can also be described as alternating between two values or rotating around a central value.

Typically, the mathematical formula for the moment of inertia is

T = 2 π √(I / mgd)

Therefore, a moment of inertia

I = 9.00×10-3 + md^2 ;

I=9.00*10^{-3}+ 0.5 * 0.3^2

I=0.054

T=2 $\pi \sqrt{0.5*9.8*0.3}$

T=1.2042s

The period of the oscillations.T = 1.2042s

Read more about the period of the oscillations. brainly.com/question/14394641

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4 months ago

Find the unit vector in the direction of vector B=4i+2j-5k

solmaris [256]

Answer:

$\frac{4}{\sqrt{45} } i\,+\frac{2}{\sqrt{45} } j-\frac{5}{\sqrt{45} } k$

Explanation:

for the unit vector, we need to divide the given vector by its norm, because it should be in the SAME direction as the original vector, but of magnitude "1".

We notice that the norm of the given vector is:

$\sqrt{4^2+2^2+(-5)^2} =\sqrt{45}$