Fnet=fa-fr
=47-23
=24n
W=F∆Xcos°
=24n×0.025cos0
=0.6J
The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.
Hope this helps!</span>
Answer:
Torque is 93 Nm anticlockwise.
Explanation:
We have value of torque is cross product of position vector and force vector.
A force of 38 N, directed 30° above the x axis in the x-y plane.
Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j
A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.
Position vector, r = 4.9 i
Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm
So Torque is 93 Nm anticlockwise.
Explanation:
F=(Gmm)/(r^2)
larger the mass stronger the force. An object with a large mass will produce a large force. A small mass will produce a small force.
Answer:
the answer would be B your welcome
Explanation:
