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nata0808 [166]
3 years ago
10

Need help with this one question!​

Physics
2 answers:
Lelu [443]3 years ago
8 0

Answer:

Actual Mechanical Advantage

Explanation:

AMA=mg/F(applied)

lisov135 [29]3 years ago
4 0
I think the following ratio is called, “actual mechanical advantage.”
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A man does 500 J of work pushing a car a distance of 2 m. How much force does he apply? Assume there is no friction.
Dmitry [639]

The correct answer is A. 250N

Work is a product of force and distance.

That is, work done=force×distance

Therefore substituting for the values in the question:

500J=force×2m

force= 500Nm/2m=250N

another unit for work done is Nm as force as the SI unit of force is newtons and distance in meters

6 0
3 years ago
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A description of both speed and direction
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3 years ago
A carnot engine has an efficiency of 50% when its sink temperature is 27°C. The temperature of source is: a) 300°C b) 327°C c) 2
hram777 [196]
<h2>Answer:</h2>

327 degrees

<em>Have a great day! </em>

5 0
3 years ago
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.0 m on a frictionless horizontal su
DerKrebs [107]
<span>The centripetal force for such an arrangement can be found through the equation Fc = mv^2/r where m is the mass of the rotating object, v is that object's velocity, and r is the radius of rotation. In this case, we know that the maximum Fc that can be tolerated by the cord is 64N. Thus we set the equation up and solve for the value of v for which Fc = 64.
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3 0
3 years ago
An electromagnet produces a magnetic eld of 0.95 T in a cylindrical region of radius 3.0 cm between its poles. A straight wire c
Daniel [21]

Answer:

0.855 N

Explanation:

Using

F = BILsinФ.................... Equation 1

Where F = magnitude of the force exerted on the wire, B = magnetic Field, I = current, L = Length of the wire in the magnetic Field, Ф = angle between the wire and the magnetic field.

Given: B = 0.95 T, I = 15.0 A, L = 2r, r = radius = 3.0 cm = 0.03 m L = 2×0.03 = 0.06 m, Ф = 90° (perpendicular)

Substitute into equation 1

F = 0.95(15)(0.06)sin90°

F = 0.855 N.

Hence the magnitude of force that is exerted on the wire = 0.855 N

6 0
3 years ago
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