<span>Car B has a greater momentum than car A.
Since, momentum = mass * velocity
mass of both car A and B is same, velocity of B is greater than A.
So, momentum of car B = 1200 * 25 = 30,000 kg-km/h is greater than </span>momentum of car A = 1200 * 22 = 26400 kg-km/h
Consider velocity to the right as positive.
First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right
Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left
Total momentum of the system is
P = m₁v₁ + m₂v₂
= 4*2 + 8*(-3)
= -16 (kg-m)/s
Let v (m/s) be the velocity of the center of mass of the 2-block system.
Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s
Answer:
The center of mass is moving at 1.33 m/s to the left.
Answer:
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Explanation:
The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.
Given are
<em> mass of the student 73 kg</em>
<em> height of water glide 11.8 m</em>
<em> work done as -5.5*10³ J</em>
Have to find speed at which the student goes down the glide.
According to<em> Law of Conservation of energy</em>,
K.E =P.E+Work Done
mv²/2=mgh +W
Rearranging the above eqn for v
v = √2(gh+W/m)
Substituting values,
V = 12.48 m/s.
<em>The velocity with which the student goes down the bottom of glide is 12.48m/s.</em>
Answer:
The pH scale was invented by Svante Arrhenius is false.
Explanation :
because the pH scale was invented by Soren Sorensen
Answer:
a=1.03 m/s²
Explanation:
given required
dist=22.1 cm a=?
m1=2.1 kg
m2=1.56 kg
m3=1.93 kg
g=9.8 m/s²
solution
there are three forces on this system so we can solve by using newton's second law as follows
t1,t2,and weight of are the only forces acted on the system,
if we take the system on the left mass m3
-m3a=t2-m3g
-1.93 kg×a=t2-1.93 kg×9.8 m/s²
-1.93 kg×a=t2-18.91 N................................ eq 1
take at the right mass m2
m2a=t2-m2×g
1.56 kg×a=t2-1.56 kg×9.8 m/s²
1.56 kg×a=t2-15.288 N...................................2
add the two equations simultaneously and then solve for a,
-1×(-1.93 kg×a=t2-18.91 N) multiply by -1 the first and add the two equations
1.56 kg×a=t2-15.288 N
3.49 kg×a=3.622 N
a=1.03 m/s²
