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MAVERICK [17]
1 year ago
5

How does fabric softener help prevent static electricity?

Physics
1 answer:
Olin [163]1 year ago
4 0

Answer:

Dryer sheets stop static cling by absorbing static electricity formed by different fabrics during your dryer cycle. The fabric softeners that coat dryer sheets are positively charged ions to balance the electrons and ions that cause static cling, leaving you with soft clothes without the static.

Explanation:

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Which one of the following scenarios accurately describes a condition in which resonance can occur? A. A column of air has a hei
ollegr [7]
The correct option is D.
Resonance is a phenomenon in which a vibrating system or an external force induces another system to vibrate at greater amplitude at particular frequencies. 
When a tuning fork is struck with another object, the tuning fork will start to vibrate as a result of the force that is exerted by the object used to struck it. This type of vibration, without direct excitation by a man is an example of resonance.
8 0
3 years ago
A light bulb has 0.25 A of current using a voltage of 120 V. What is the power rating for this bulb?
julsineya [31]

We can't tell what RATING is printed on the package of bulbs, but right now, the bulb is dissipating IxE= 30 watts of heat and light.

6 0
2 years ago
Please answer these two questions ASAP!! Will mark brainliest and give points!
maw [93]
Counter clockwise torque is 360Nm. 
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6 0
3 years ago
Read 2 more answers
A gazelle is running at 17.46 m/s. He sees a lion and accelerates at -1.49 m/s/s,
Vsevolod [243]

Answer:

V=21.0211m/s

Explanation:

Use V=vi+at

So, V=17.46m/s+(1.49m/s^{2})(2.39s)= 21.0211m/s

5 0
2 years ago
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A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

PV=nRT

For a gas

P_{1}V_{1}=nRT_{1}

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

10\times V=nR\times286....(I)

When the temperature of the gas is increased

Then,

P_{2}V_{2}=\dfrac{n}{2}RT_{2}....(II)

Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0
2 years ago
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