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MAVERICK [17]
2 years ago
5

How does fabric softener help prevent static electricity?

Physics
1 answer:
Olin [163]2 years ago
4 0

Answer:

Dryer sheets stop static cling by absorbing static electricity formed by different fabrics during your dryer cycle. The fabric softeners that coat dryer sheets are positively charged ions to balance the electrons and ions that cause static cling, leaving you with soft clothes without the static.

Explanation:

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A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s
Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

Explanation:

Given

Weight of sledge hammer = 2.30 kilogram

Speed of sledge hammer = 62.7 meter per second

Kinetic energy is equal to half the product of mass and velocity square

K E = \frac{1}{2} mv^2

Substituting the value of mass and velocity, we get -

KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

\frac{1}{4} * 4520.9835\\= 1130.246

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

8 0
3 years ago
Read 2 more answers
Which of the following is NOT a unit of measurement for speed?
Dmitriy789 [7]

I don't see any units of measurement or speed I don't see anything

3 0
3 years ago
Read 2 more answers
Les changements d'état de la matière
ale4655 [162]

Answer:

Les changements d'état sont des changements physiques. Ils se produisent lorsque la matière absorbe ou perd de l'énergie. Les processus dans lesquels la matière change entre les états liquide et solide sont la congélation et la fusion. Les processus dans lesquels la matière change entre les états liquide et gazeux sont la vaporisation, l'évaporation et la condensation.

Im not french and I used translate so if it messes up with the translation, I am sorry

5 0
3 years ago
Hooke's law describes an ideal spring. Many real springs are better described by the restoring force (F Sp ) s =−kΔs−q(Δs) 3 (p)
Montano1993 [528]

Answer with Explanation:

We are given that

Restoring force,(FS_p)s=-k\Delta s-q(\Delta s)^3

k=350N/m

q=750 N/m^3

We have to find the work must you do to compress this spring 15 cm.

\Delta s=15 cm=0.15 m

Using 1 m=100 cm

Work done=\int_{0}^{0.15}-Fd(\Delta s)

W=-\int_{0}^{0.15}(-k\Delta s-q(\Delta s)^3))d(\Delta s)

W=k[\frac{(\Delta s)^2}{2}]^{0.15}_{0}+q[\frac{(\Delta s)^4}{4}]^{0.15}_{0}

W=0.01125k+0.000127q=0.01125\times 350+0.000127\times 750

W=4.033 J

Ideal spring work=0.5k(\Delta s)^2=0.5\times 350\times (0.15)^2=3.938 J

Percentage increase in work=\frac{4.033-3.938}{3.928}\times 100=2.4%

6 0
4 years ago
A jeweler is determining the optical properties of an unknown blue gemstone. She uses an angle of incidence of 62°, and measures
Juliette [100K]

Answer:

n = 1.76

Explanation:

According to the rule of ( n1 sin theta1 = n2 sin theta2 )

we know both angles so we insert them to the law and apply n1 = 1

so 1/2 = n2 sin 62 and we get the final answer

3 0
4 years ago
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