1 answer:
1. Rewrite the system:
x+12y=68 (i)
x=8y-12 (ii)
2. Let's substitute the equation (ii) into the equation (i):
x+12y=68
(8y-12)+12y=68
3. Then, you have:
8y-12+12y=68
4. When you clear "y", you have:
20y-12=68
20y=68+12
20y=80
y=80/20
y=4
5. You already have the value of "y". Now, you must substitute this value into the equation (ii):
x=8y-12
x=8(4)-12
x=32-12
x=20
6. Therefore, the result is:
x=20
y=4
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Fifteen and sixty two thousanths
Answer:
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Step-by-step explanation:
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Are you sure this question is right? there are no negatives? i’m pretty sure the answer is 72 but if i’m wrong, i’m sorry.
Sure! but unfortunately the picture is blank. not sure if it’s just my screen
C
The numbers on the left represent 10 times that number
The numbers on the right are added to the end of the number on the left so
3I1=31 and 4I8=48 and 3I 1 1 2= 31 31 32