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shutvik [7]
3 years ago
12

Completing the sqaure x^2+14x+34

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

-7-√15

Step-by-step explanation:

First move the constant to the right hand side and change it's sign

x^2+14x=-34

Then add (14/2)^2 or 7^2 to both sides

x^2+14x+49=-34+49

Then factor the expression

(x+7)^2=-34+49

Then solve (x+7)^2=15

You should get:

x=-√15-7

or

x=√15-7

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What is the value of the expression below when w = 3?<br> 10w2 + 9w - 2
NISA [10]

Answer:

10w2+9w-2

10*w*2+(9*w)-2

10*3*2+(9*3)-2

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Step-by-step explanation:

7 0
3 years ago
Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)
vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\

Apply substitution to get

y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right)  + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x)  + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x)  + \left(a - 6b\right)\cos(x) = \sin(x)\\\\

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a  -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

8 0
2 years ago
A rectangular garden has an area of 144ft. If the base is 8ft long, what is the height ?
Alekssandra [29.7K]
A. 18
Formula for area is LxW.
Divide 144 by 8 and you get 18.
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2 years ago
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