Answer:
dfhjkbfgv u u u ucuvvcuvuvuc y y y y y y y y y h u h h u u h h h h uu uu u u uu
The correct answer for this question is this one: "<span>y = -x + 2"</span>
<span> y - intercept = (0,2) slope = -1
y = mx + b
2 = -1 (0) + b
b = 2
so the equation of the line is
<u>y = -x + 2</u></span>
Hope this helps answer your question and have a nice day ahead.
180 I think not sure if I am right
The value of the derivative at the maximum or minimum for a continuous function must be zero.
<h3>What happens with the derivative at the maximum of minimum?</h3>
So, remember that the derivative at a given value gives the slope of a tangent line to the curve at that point.
Now, also remember that maximums or minimums are points where the behavior of the curve changes (it stops going up and starts going down or things like that).
If you draw the tangent line to these points, you will see that you end with horizontal lines. And the slope of a horizontal line is zero.
So we conclude that the value of the derivative at the maximum or minimum for a continuous function must be zero.
If you want to learn more about maximums and minimums, you can read:
brainly.com/question/24701109
To solve this equation you need to first start by writing out the f(x)-g(X).
The equation should be 2x^2-4x-5+2x.
You then want to simplify the equation, I got 2x^2-2x-5.
You then want to plug in the x=5 for all the x's in the equation.
2(5)^2-2(5)-5 would be the equation.
The answer you get should be 35.
