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faust18 [17]
3 years ago
15

Help please!

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

Step-by-step explanation:

Sry but I only did 1,2,5,6,7&8

But am not sure if am correct just try

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Find the commission on a sale of $8,432 at 1 1/2% commission.
IrinaK [193]

Answer:

5621.33333333

Step-by-step explanation:

This is only the right answer if you are asking how much money 1 1/2 % of 8432 is.

But i think i'm right ^-^

6 0
2 years ago
How to do this pls:( using PEMDAS
Kryger [21]

Answer: x y

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7 0
3 years ago
What is the area of this triangle?
Contact [7]

Answer: 43.5

Step-by-step explanation:

A=\frac{1}{2}(8)(12)(\sin 65^{\circ}) \approx \boxed{43.5}

6 0
2 years ago
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
2 years ago
How can you solve an equation with the variable on both sides plz help
Sergeeva-Olga [200]
I don't know if this is the right one but i hope this helps. this is how i learned it. 
step 1=get variables on one side oof the equal sign by using inverse operation (add or subtract smaller variable) 
step 2= get constants away from variable to the other side of the equal sign by using inverse operations (add or subtract constant) 
step 3: isolate the variable using inverse operation (multiply or divide) 
7 0
3 years ago
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