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3 years ago

Can someone please help with this?

Mathematics

1 answer:

Mkey [24]3 years ago

6 0

Answer:

true

Step-by-step explanation:

first find the median of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

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6(x+7)+4=-8(x-5)-2 solve for x

NikAS [45]

Answer:

x=-4/7

Step-by-step explanation:

We are given an equation as

6(x+7)+4=-8(x-5)-2

and asked to solve for x

Simplify to get

Distribute 6 over x+7 and on right side -8 over x-5

6x+42+4 = -8x+40-2

Take -8x to left side to become +8x and 46 to right side to become -46

Grouping like terms

14x = 38-46 = -8

Divide by 14

x = -8/14 = -4/7

Since this is an equation, we get a single value for x

and answer is -4/7

4 0

3 years ago

Help please thank you

mash [69]

Answer:

1/5

Step-by-step explanation:

Scale factor= Image/Object

Figure C

_______(Take any of the sides of both figures)

Figure B

Scale factor= 1.5 1

___ = __

7.5 5

5 0

3 years ago

Read 2 more answers

Hellllllp I need this answer ADAP‼️‼️ :(((

Ede4ka [16]

Answer:

$m\angle D=64^{\circ}$

Step-by-step explanation:

Given

$\triangle ABE\sim \triangle TCD$

Similar triangles have conruent corresponding angles, so

$m\angle A=m\angle T=61^{\circ}\\ \\m\angle B=m\angle C=55^{\circ}\\ \\m\angle E=m\angle D$

The sum of the measures of all interior angles of the triangle is always equal to 180°, so

$m\angle T+m\angle C+m\angle D=180^{\circ}\\ \\61^{\circ}+55^{\circ}+m\angle D=180^{\circ}\\ \\m\angle D=180^{\circ}-61^{\circ}-55^{\circ}=64^{\circ}$

6 0

3 years ago

Using the work I’ve done so far as reference, show that neither triangle is a vector translation of the other. Draw a diagram.

notsponge [240]

When we move the triangle RPQ horizontally or vertically or side ways, the triangle will not coincide with the triangle KLM.

Similarly, if we move the triangle KLM horizontally or vertically or side ways, the triangle will not coincide with the triangle RPQ.

Hence, both the triangles are not vector translations of each other.

3 0

1 year ago

-7 2/3 + (-5 1/2) +8 3/4

Vika [28.1K]

Answer:

$-4\frac{5}{12}$

Step-by-step explanation:

Here we have three terms, none with matching denominators.

Now we have to find the least common multiple of 3, 2, and 4. We can ignore the 2 here because the 4 takes care of that. The least common multiple of 3 and 4 is 12. 12 is also divisible by 2, so we've fulfilled those terms.

Now, let's get to work. We have to convert all of those mixed numbers into fractions with a denominator of 12. I'll skip the explanation and just do the work step by step. Ask questions if you are unsure of something.

First, we'll just put them all in a row.

$-7\frac{2}{3} -5\frac{1}{2} +8\frac{3}{4}$

Next, I'm going to put them in the forms of improper fractions, just to make this a bit less cluttered.

$-\frac{23}{3} -\frac{11}{2} +\frac{35}{4}$

Then, I'll adjust the denominators of the fractions by multiplying the whole fraction by whatever it takes to make that denominator 12. Remember, multiply the numerator and the denominator by the same number.

$-\frac{23}{3}(\frac{4}{4})-\frac{11}{2}(\frac{6}{6})+\frac{35}{4}(\frac{3}{3})$

$-\frac{92}{12} -\frac{66}{12} +\frac{105}{12}$

Now, let's add them together.

$-\frac{53}{12}$

You can leave this as an improper fraction, but I'm going to put this into mixed number form for you.

$-4\frac{5}{12}$

3 0

4 years ago