Answer:
Step-by-step explanation:
Given that x = no of movies high school students watched is N(6.8, 1.8)
Sample size = 36 and hence std error = 1.8/6 = 0.3
(two tailed test)
Mean difference = 6.2-6.8 = -0.6
Test statistic z = -0.6/0.3= -2
p value = 0.02275
Since p <0.05 we reject H0.
There is evidence to show that college students watch fewer movies a month than high school students
Answer:
Step-by-step explanation:
First let's find the value of 'p-q':
To find |p-q| (module of 'p-q'), we can use the formula:
Where 'a' is the coefficient of 'i' and 'b' is the coefficient of 'j'
So we have:
Now, we need to find the module of p and the module of q:
Then, evaluating |p-q|-{|p|-|q|}, we have:
Answer:
0.97
Step-by-step explanation:
Given that a homeowner has two smoke detector alarms installed, one in the dining room (adjacent to the kitchen) and one in an upstairs bedroom (above the kitchen). If cooking produces smoke in the kitchen, the probability of setting off the dining room alarm (D) is .95. The probability of setting off the bedroom alarm (B) is .40.
Both alarms are independent of each other.
Probability for smoke detection=P(any one alarm rings)
=P(Kitchen alarm sets off)+P(bed room alarm sets off)-P(Both sets off)
Since both are independent
P(Both) =
Probability for smoke detection
= 0.95+0.40-0.38
=0.97