2 years ago

How do I get the third mark have I done something wrong?

Mathematics

1 answer:

Anna11 [10]2 years ago

8 0

Answer:

C (- 4, - 2 )

Step-by-step explanation:

(c)

the x- coordinate of A is - 4

the y- coordinate of B is - 2

coordinates of C = (- 4, - 2 )

You might be interested in

Which two values of x are roots of the polynomial below? x^2-3x+5

Gemiola [76]

Given:

Polynomial $x^2-3x+5$

To find:

The values of x.

Solution:

$x^2-3x+5=0$

Quadratic equation formula:

$$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here $a=1, b=-3, c=5$ .

Substitute the values in the formula, we get

$$x=\frac{-(-3) \pm \sqrt{(-3)^{2}-4 \cdot 1 \cdot 5}}{2 \cdot 1}$

$$x=\frac{3 \pm \sqrt{9-20}}{2}$

$$x=\frac{3 \pm \sqrt{-11}}{2}$

$$x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$

Option E and option F are the roots of the polynomial.

The values of x are $x=\frac{3 - \sqrt{-11}}{2} \ \text{and} \ x=\frac{3 + \sqrt{-11}}{2}$ .

7 0

3 years ago

Solve the following system of equations.

sasho [114]

X is minus 2
y is equal to 1

4 0

3 years ago

How to find the solution(s) to:x^2=64

KATRIN_1 [288]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Factorise fully the following:<br> a) x² - 2x<br> b) 6x^2+ 12x<br> c) 3x^3- 9x<br> d) 4x^2+ 28x^3

mezya [45]

Answer:

a) x(x - 2)

b) 6x(x + 2)

c) 3x(x^2-3)

d) (2x)(2x)(1+7x)

Step-by-step explanation:

8 0

3 years ago

Complete the solution of the equation find the value of y when x equals negative 30. -2x-3y=42

Rama09 [41]

-2 (-30) - 3y = 42
60 - 3y = 42
-3y = -18
y = 6

7 0

3 years ago

Read 2 more answers