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3 years ago

Log4 216-log4 8 =log4 x

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

216/8= 27. X= 27. Subtract you divide

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PLEASE HELP!!!!! I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER

Luda [366]

Answer:

Step-by-step explanation:

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3 years ago

A car was Skid to a half a uniform rate of -9.4 m/s ^2 squared if the measure skid marks that are 34 m long with what speed is t

babymother [125]

Answer:

vi = 25.28 m/s

Step-by-step explanation:

a = -9.4 m/s²

x = 34 m

vf = 0 m/s

vi = ?

We can apply the equation

vf² = vi² + 2*a*x

⇒ vi = √(vf² - 2*a*x)

⇒ vi = √((0 m/s)² - 2*(-9.4 m/s²)*34 m)

⇒ vi = 25.28 m/s

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3 years ago

What’s a mode in a dit plot

Mariana [72]

Answer:

You can use it to plot to find mean, median, mode, and outliers of data sets.

Step-by-step explanation:

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3 years ago

Read 2 more answers

True or false? The graph represents a function<br> 5<br> -5<br> A True<br> B. False

Daniel [21]

Answer:

True

Step-by-step explanation:

It passes the vertical line test, meaning you can draw a vertical line anywhere on the graph and it will only intersect at one point

this means that for every input (x value) there is only one output (y value)

6 0

2 years ago

The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

3 0

3 years ago