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Ilya [14]
3 years ago
7

In 2000, the total number of employees working for

Mathematics
2 answers:
Andrew [12]3 years ago
7 0

Answer:

680,000

679,967 rounded to the nearest thousand is 680,000.

So, there are around 680,000 employees working for US Airlines. Hope it helps!

OLga [1]3 years ago
5 0

Answer:

680,000

Step-by-step explanation:

Look at the hundreds place if it's 5 or higher you round up the thousands place by one. Every place to the right of the hundreds place turns into a zero.

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Ignoring those who said they weren't sure, there were 297 men asked, and 183 said yes, they had driven a car when they probably
USPshnik [31]

Answer:

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

Step-by-step explanation:

Information given  

n=297 represent the random sample of male taken

X=183 represent the  men who said yes, they had driven a car when they probably had too much alcohol

\hat p=\frac{183}{297}=0.616 estimated proportion of men who said yes, they had driven a car when they probably had too much alcohol

p_o=0.5 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Hypothesis to test

We need to conduct a hypothesis in order to test the claim that the majority of men in the population (that is, more than half) would say that they had driven a car when they probably had too much alcohol, and the system of hypothesis are:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

After replace we got:

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

Decision

We have a right tailed test so then the p value would be:  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

7 0
3 years ago
Find the equation of the linear function represented by the table below in slope-intercept form.
alexandr402 [8]

Answer: The equation is y = 3x + 3

Step-by-step explanation:

3 0
3 years ago
A box of crayons costs $1.75, including tax. Mr. Valentino wants to purchase boxes of crayons for his class and has a $25 budget
densk [106]

Answer:

1.75x ≤ 25

Step-by-step explanation:

8 0
4 years ago
Lily has a bag of 30 marbles. 40% are red, 30% are green, and 30% are blue. How many marbles are green and red combined?​
RoseWind [281]
30% of the 30 marbles is nine and 9-30 = 21 so your answer is 21
3 0
3 years ago
Any one that knows this please help thanks!
nignag [31]

You just need to plug the values: you have to multiply x and y^2, and then divide the result by -3.

So, if y=2, we have y^2=4

Which means that xy^2 = 5\cdot 4 = 20

And the final answer is \frac{20}{-3}

3 0
3 years ago
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