Answer:
The given electronic configuration is long hand notation.
Explanation:
Long-hand notation of representing electronic configuration is defined as the arrangement of total number of electrons that are present in an element.
Noble-gas notation of representing electronic configuration is defined as the arrangement of valence electrons in the element. The core electrons are represented as the previous noble gas of the element that is considered.
The given electronic configuration of potassium (K):
The above configuration has all the electrons that are contained in the nucleus of an element. Thus, this configuration is a long-hand notation.
I believe those all look correct!
Answer:
5.45*10⁻⁴ moles of silane gas (SiH₄) are present in 8.68 mL measured at 18°C and 1.50 atm.
Explanation:
An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
In this case:
- P= 1.5 atm
- V= 8.68 mL= 0.00868 L (being 1000 mL= 1 L)
- n= ?
- R= 0.082

- T= 18 C= 291 K (being 0 C= 273 K)
Replacing:
1.5 atm* 0.00868 L= n* 0.082
*291 K
Solving:

n= 5.45*10⁻⁴ moles
<u><em>5.45*10⁻⁴ moles of silane gas (SiH₄) are present in 8.68 mL measured at 18°C and 1.50 atm.</em></u>
<span>air = 70 % N2
exhaled air =70%N2 + some less O2 compared to only air
2H2O2=2H2O+O2
NaHCO3=2NaHCO3 → Na2CO3 + H2O + CO2 = No O2 gas from decomposition
ssoooo NaHCO3 <exhaled air <air <H2O2
SO sorry for the long wait, hope I helped.
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