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Marizza181 [45]
3 years ago
10

What is the difference between an exergonic reaction and an endergonic reaction?

Chemistry
2 answers:
anyanavicka [17]3 years ago
8 0

here are the answers

1 B

2 C

3 D

4 A

Marina CMI [18]3 years ago
7 0

The difference between an exergonic reaction and an endergonic reaction is that an exergonic reaction involves release of energy, while an endergonic reaction involves absorption of energy.

 

<span>In an </span>exergonic reaction, energy is released to the surroundings. The bonds being formed are stronger than the bonds being broken. In an endergonic reaction, energy is absorbed from the surroundings.

 

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

You might be interested in
what is the difference between the number of electrons in an atom of selenium, Se and the number of electrons in an atom of alum
ELEN [110]

Answer:

Well, electrons can be converted into a atomic number so if SE atomic number is 34 that means it has 34 electrons. AI has a atomic number of 13 meaning it has 13 electrons. So the difference is that SE has more electrons then AI.

5 0
3 years ago
Please help
ludmilkaskok [199]

Answer: The molecular formula will be C_3H_9

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.  

The empirical formula is CH_3

The empirical weight of CH_3 = 1(12)+3(1)= 15g.

The molecular weight = 45.0 g/mole

Now we have to calculate the molecular formula:

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{45}{15}=3

The molecular formula will be=3\times CH_3=C_3H_9

Thus molecular formula will be C_3H_9

6 0
3 years ago
For an alloy that consists of 78.2 g copper, 103.5 g zinc, and 2.8 g lead, what are the concentrations of (a) Cu, (b) Zn, and (c
TEA [102]

Answer:

Explanation:

Mass percent is defined as the mass of an element divided by the sum of masses of all the elements multiplied by 100. It is generally used to define the concentration. It does not depend on concentration.

It is given as;

Mass percent = (mass of an element / Total mass of the compound ) × 100

Mass of  compound (alloy) = 78.2 g copper  + 103.5 g zinc +2.8 g lead = 184.5 g

(a) Cu

Mass of Cu = 78.2

Mass percent = (78.2 / 184.5) * 100 = 42.38%

(a) Zn

Mass of Zn = 103.5

Mass percent = (103.5 / 184.5) * 100 = 56.10%

(c) Pb

Mass of Pb = 2.8

Mass percent = (2.8 / 184.5) * 100 = 1.52%

8 0
4 years ago
With 143.6 grams of acetylene and an excess amount of oxygen gas, what is the percent yeild of carbon dioxide if the actual yiel
nata0808 [166]

Answer:

93.28%

Explanation:

To solve the percent yield we need to find theoretical yield:

<em>Percent yield = Actual Yield (452.78g) / Theoretical yield * 100</em>

<em />

Theoretical yield is obtained converting the mass of acetylene to moles and using the balanced equation determine the moles of CO₂ produced assuming a 100% of reaction:

<em>Moles acetylene (Molar mass: 26.04g/mol)</em>

143.6g C₂H₂ * (1mol / 26.04g) = 5.515 moles C₂H₂

<em>Moles CO₂:</em>

5.515 moles C₂H₂ * (4 moles CO₂ / 2mol C₂H₂) = 11.029moles CO₂

<em>Mass CO₂ (Molar mass: 44.01g/mol):</em>

11.029moles CO₂  * (44.01g / mol) = 485.39g CO₂ is theoretical yield

Percent yield is:

Percent yield = 452.78g / 485.39g * 100

= 93.28%

8 0
3 years ago
Trevor, Neville Longbottom’s pet toad, has a mass of 13.6 kg. Trevor jumps into a large cylinder containing water. The water lev
nasty-shy [4]

Answer:

5.44 kg/L

Explanation:

Mass = 13.6 kg

Change in water level as a result of Trevor = Volume of Trevor = 2.50 L

Density = ?

The relationship between the three parameters is given as;

Density = Mass  /  Volume

Density = 13.6 / 2.5

Density = 5.44 kg/L

8 0
4 years ago
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