Answer:
1.87x10⁻³ M SO₄²⁻
Explanation:
The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:
SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)
<em>Where 1 mole of SO₄²⁻ reacts per mole of Ba²⁺</em>
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To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.
Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).
<em>Moles Ba²⁺:</em>
7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻
<em>Molarity SO₄²⁻:</em>
As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:
1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =
<h3> 1.87x10⁻³ M SO₄²⁻</h3>
You are going to fall, face first on the ground.
Answer:
0.015% and 0.012%
Explanation:
using simultaneous equation
Answer:
CO(g) + 2H₂(g) → CH₃OH(l)
Explanation:
Carbon monoxide has molecular formula CO, molecular hydrogen has formula H₂, and methanol is CH₃OH.
The reactants are CO and H₂ and the product CH₃OH:
CO(g) + H₂(g) → CH₃OH(l)
To balance the equation, the elements must have the same amount on each side. C and O are balanced, but there is 4H in the product and only 2 in the reactant, so we multiply H₂ for 2:
CO(g) + 2H₂(g) → CH₃OH(l)
And the equation is balanced.
Mass SrBr2 = 247.42 g/mol x 1.36 mol
<span>= 336 g</span>
