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Anit [1.1K]
3 years ago
12

Be sure to answer all parts. the average atomic mass of nitrogen is 14.0067. the atomic masses of the two stable isotopes of nit

rogen, 14n and 15n, are 14.003074002 and 15.00010897 amu, respectively. use this information to determine the percent abundance of 14n.
Chemistry
1 answer:
Sergio039 [100]3 years ago
8 0
To answe this question, we will assume that the percentage abundance of 14n is y. Since the percentage abundance of 14n + percentage abundance of 15n = 100% = 1
Therefore, percentage abundance of 15n = 1 - y.

Now we know that the average atomic mass of nitrogen is 14.0067
Therefore:
average atomic mass of nitrogen = atomic mass of 14n x its percentage abundance + atomic mass of 14n x its percentage abundance
14.0067 = 14.003074002 y + <span>15.00010897 (1 - y)
</span>14.0067 = 14.003074002 y + 15.00010897 - 15.00010897 y
14.0067 - 15.00010897 = 14.003074002 y  - 15.00010897 y 
<span>0.99703497 y =  0.99340897
</span>
Therefore y = <span> 0.99636

Based on this, the percentage abundance of 14n is </span> 0.99636x100= <span>99.636%
while percentage abundance of 15n = 100% - </span>99.636% = <span>0.364%</span>
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How many moles of O2 are required to react with 6.6 moles of H2?
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<u>Answer: </u>

<u>For 1:</u> 3.3 moles of oxygen gas is required.

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  • <u>For 2:</u> When 7.0 moles of O_2 is reacted.

By Stoichiometry of the above reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas.

So, 7 moles of oxygen gas will react with = \frac{2}{1}\times 7=14mol of hydrogen gas.

Hence, 14 moles of hydrogen gas is required.

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Explanation:

Step 1: Given  and required data

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Step 2: Calculate the molarity (M) of the solution

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